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My name is Ann [436]
3 years ago
6

Explain how temperature and amount of precipitation can affect the type of plants and animals found in the grassland biome?

Chemistry
1 answer:
MArishka [77]3 years ago
3 0
Temperature grasslands have hot summers and cold winters. Summer temperatures can be well over 100 degrees Fahrenheit, while winter temperatures can be as low as -40 degrees Fahrenheit. They typically have between 10 and 35 inches of precipitation a year, much of it occurring in the late spring and early summer. As climate conditions shift geographically so will the distributions of many plants and animals. The relatively flat terrain of grasslands increases vulnerability to climate change impacts, because habitats and species must migrate long distances to compensate for temperature shift.
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What is the bond order for a single covalent bond?​
hram777 [196]

Answer:

We typically represent covalent bonds with a dash ( - ) between the atoms. This indicates a single bond. Ex: Cl - Cl

Single bond, double bond, triple bond.

Explanation:

We call it a single covalent bond because the atoms are sharing a single pair of electrons.

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3 years ago
Select which of the following are used to determine the age of the Earth. Select 3.
saveliy_v [14]

Meteorites discovered on earth

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3 years ago
A scientist did an investigation on the growth of koi fish. He selected forty newly hatched koi from the same clutch of eggs. He
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3 years ago
The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat
WINSTONCH [101]

Answer:

Final temperature = 43.53^{\circ} C

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1

Put all the values,

T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C

So, the final temperature is equal to 43.53^{\circ} C.

8 0
3 years ago
Calculate the molecular weight when a gas at 25.0 ∘C and 752 mmHg has a density of 1.053 g/L . Express your answer using three s
stiks02 [169]

Answer:

26.0 g/mol is the molar mass of the gas

Explanation:

We have to combine density data with the Ideal Gases Law equation to solve this:

P . V = n . R .T

Let's convert the pressure mmHg to atm by a rule of three:

760 mmHg ____ 1 atm

752 mmHg ____ (752 . 1)/760 =  0.989 atm

In density we know that 1 L, occupies 1.053 grams of gas, but we don't know the moles.

Moles = Mass / molar mass.

We can replace density data as this in the equation:

0.989 atm . 1L = (1.053 g / x ) . 0.082 L.atm/mol.K . 298K

(0.989 atm . 1L) / (0.082 L.atm/mol.K . 298K) = 1.053 g / x

0.0405 mol = 1.053 g / x

x =  1.053 g / 0.0405  mol = 26 g/mol

7 0
3 years ago
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