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77julia77 [94]
3 years ago
13

What is the mass of 1 mole of Pb?

Chemistry
2 answers:
Volgvan3 years ago
8 0

Answer:

207.2 g

Explanation:

The mass of 1 mole of lead is given by its molar mass, which  is 207.2 g/mol. This is an average molar mass, corresponding to the weighted average of the 4 lead isotopes, ²⁰⁴Pb, ²⁰⁶Pb, ²⁰⁷Pb, ²⁰⁸Pb, considering their abundance in nature. The mass of 1 mole of Pb is:

1 mol × (207.2 g/mol) = 207.2 g

s2008m [1.1K]3 years ago
3 0
<span>How many moles Pb in 1 grams? The answer is 0.0048262548262548. We assume you are converting between moles Pb and gram. 1 mole is equal to 1 moles Pb, or 207.2 grams.</span>
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scoray [572]

Answer:

<u>d) 1.8 atm</u>

Explanation:

<u>According to Boyle's Law,</u>

  • P₁/T₁ = P₂/T₂

Here, we are given :

  1. <u>P₁ = 1.5 atm</u>
  2. <u>T₁ = 25°C = 298 K</u>
  3. <u>T₂ = 75°C = 348 K</u>

<u />

<u>Solving</u>

  • P₂ = P₁T₂/T₁
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3 0
2 years ago
What is the mass of 1.58 moles of CH4
HACTEHA [7]
<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})
  2. Multiply/Divide:                 \displaystyle 25.359 \ g \ CH_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

4 0
3 years ago
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Assoli18 [71]

Carbon-12, Carbon-13 and Carbon-14 are examples of isotopes of the carbon atom.


6 0
3 years ago
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