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jekas [21]
3 years ago
6

What is the distance between A and B? Round your answer to the nearest hundredth.

Mathematics
1 answer:
Reika [66]3 years ago
6 0
An extension of the Pythagorean Theorem results in what is the so-called "distance formula".

d^2=(x2-x1)^2+(y2-y1)^2, in this case you have points (-2,4) and (2,0) so:

d^2=(2--2)^2+(0-4)^2

d^2=4^2+(-4)^2

d^2=16+16

d^2=2*16

d=√32  units

d=√(2*16)

d=4√2 units

d≈5.66 units (to nearest hundredth of a unit)
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Step-by-step explanation:

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7 0
2 years ago
Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8
goblinko [34]
\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y  = \frac{17}{14} } \atop {x+7y=8}} \right.

To solve this system by substitution, first isolate x in the second equation.

x+7y=8
x+7y-7y=8-7y
x=8-7y

Now, plug this expression (8-7y) for x in the top equation to solve for y.

\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}
3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}
72-63y+8y=17
72-55y=17
-55y=17-72
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Now that you have y, plug it into the second equation and solve for x.

x+7y=8
x+7(1)=8
x+7=8
x=1

Last step is to plug your x- and y-values in to both equations to check your work.

\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}

\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ;  \frac{1}{3} * \frac{8}{8} = \frac{8}{24}

\frac{9}{24} + \frac{8}{24} = \frac{17}{24}  <--True

1+7(1)=8
1+7=8   <--True

Answer:
x=1 \\ y=1
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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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4 0
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