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3 years ago

If X = 3 inches, Y = 11 inches, W = 5 inches, and Z = 5 inches, what is the area of the object?

Mathematics

1 answer:

ziro4ka [17]3 years ago

7 0

Hello i am new here how are you doing

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I cant seem to understand this. please explain :))<br> (business math)

Alex787 [66]

Answer:

$1.50 bro

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Edith is x years old. Her sister,Madison is six years older than her. Their mother is twice as old as Madison. Their aunt, Eliza

DENIUS [597]

Answer:

Step-by-step explanation:

Edith is x years old.

Her sister,Madison is six years older than her. This means that the age of Madison is x + 6

Their mother is twice as old as Madison. This means that the age of their mother is expressed as

2(x + 6)

= 2x + 12

Their aunt, Elizabeth is x years older than their mother. This means that the expression that represents Elizabeth's age in years is

2x + 12 + x

= 3x + 12

5 0

3 years ago

Determine the sum of the following series. ∑n=1[infinity](4^n+8^n/13n)

Gnoma [55]

N=1 4+7n=71 that is the answer

3 0

2 years ago

Which step is the same when constructing an inscribed square and an inscribed regular hexagon?

Colt1911 [192]

After the construction of a circle, we have to "Set the compass to the radius of the circle" so, option C is correct.

<h3>What is a regular hexagon?</h3>

A regular hexagon is defined as a closed shape consisting of six equal sides and six equal angles. The sum of the measure of angles of a regular hexagon is 120 degrees.

Steps to create an inscribed hexagon:

1: The structure needs to adjust the box thickness towards that radius.

2: Afterward moves around the outside of the circular path to just produce the 6 vertices of that similar hexagon.

"Set the compass to the radius of the circle" so, option C is correct.

Thus the above answer is correct.

Learn more about inscribed hexagons here:

brainly.com/question/21502832

#SPJ1

6 0

2 years ago

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Find the interval(s) of upward concavity on this accumulation function.

maxonik [38]

$\displaystylef(x)=\int_{0}^{x^2}\sec^2(\sqrt{x})dx \\=\int_{0}^{\sqrt{x^2}}\sec^2(u)\cdot2udu \\=2\int_{0}^{\sqrt{x^2}}\sec^2(u)du \\=2\Big[u\tan(u)-\int\tan(u)du\Big]_{0}^{\sqrt{x^2}} \\=2\Big[u\tan(u)+\ln\Big(\mathrm{abs}(\cos(u))\Big)\Big]_0^x \\=2\Big(x\tan(x)+\dfrac{1}{2}\ln\Big(\cos^2(x)\Big)\Big) \\=2x\tan(x)+\ln(\cos^2(x))$

Hope this helps.

6 0

3 years ago