Create a proportion.
Since it takes 7 minutes to print 63 pages, and half an hour is 30 minutes, you create two ratios(unit per unit) and line up the units(minutes to minutes, pages to pages).

Now you cross multiply, 63 * 30 = 1890 and 7 * x = 7x.
So we have 1890 = 7x.
Then we divide both sides by seven.

270 = x, therefore you can print 270 pages in half an hour :)
Answer:
probability at least one zero is 0.3439
Step-by-step explanation:
given data
last four digits = randomly selected
to find out
probability that for one such phone number the last four digits include at least one 0.
solution
we know there are total 10 digit
so we first find probability of non zero digit i.e.
Probability ( non zero ) = 9 /10 = 0.9
and now we find probability of none of digit zero only event happen n= 4 time in a row by multiplication rules i.e
Probability ( none zero in 4 digit ) = 
Probability ( none zero in 4 digit ) = 
Probability ( none zero in 4 digit ) = 0.6561
so we can say probability at least one zero = 1 - Probability ( none zero in 4 digit )
probability at least one zero = 1 - 0.6561
probability at least one zero is 0.3439
Answer: The answer to Number 4 is 1!
Step-by-step explanation:
First you solve for the numbers in parentheses. 16 - 7 is 9, and 2 x 4 is 8. Then you solve for the remaining numbers. So 9 - 8 is indeed 1.
Hope this helps! :)
Answer:
31 batches
Step-by-step explanation:
Find how many batches of orange punch smoothies he can make by dividing 560 by 18:
560/18
= 31.11
Since we can only have a whole number answer, round down.
So, he can make 31 batches of orange punch smoothies.
Answer:
1) C = $25 + $40 × h
2) The domain for the ≠unction is 0 ≤ h ≤ ∞
The range for the function is 25 ≤ C ≤ ∞
3) Continuous
Step-by-step explanation:
1) The given parameters are;
The base fee charged = $25
The amount charged for labor = $40/hour
The total cost for h number of hours is C = $25 + $40 × h
2) The domain for the ≠unction is 0 ≤ h ≤ ∞
The range for the function is 25 ≤ C ≤ ∞
3) The situation is continuous because the different input values of h can be infinite (from o to infinity)