Question

In a certain normal distribution of scores, the mean is 50 and the standard deviation is 6. Find the z-score corresponding to a score of 60.

Answer 1

Answer:

z-score = 1.667

Step-by-step explanation:

The provided information are:

Population mean $(\mu)$ = 50

Population standard deviation $(\sigma)$ = 6

Score (X) = 60

The formula to calculate the z-score is:

$z=\frac{X-\mu}{\sigma}$

The z- score can be calculated as:

$z=\frac{X-\mu}{\sigma}\\z=\frac{60-50}{6} \\z= 1.667$

Hence, the z-score is 1.667.