Answer:
A) Length = 110.4 mm and width = 62.1 mm
B) A = 6855.84 mm²
C) length = 114.7 mm
width = 55.8 mm
Area = 6400.26 mm²
D) Screen with aspect ratio of 16:9 is bigger
Step-by-step explanation:
A) We are told that the aspect ratio of the phone screen = 16:9. This means that the ratio of the length to the width of the screen is 16:9.
To find the side length, we will say that;
length = 16x
width = 9x
Thus, since the edges are perpendicular, then we can use pythagoras theorem since we know that the diagonal is 127 mm
Thus;
(16x)² + (9x²)] = 127²
256x² + 81x² = 16129
337x² = 16129
x² = 16129/337
x = √(16129/337)
x = 6.9
Thus;
length = 16x = 16 × 6.9 = 110.4 mm
width = 9x = 9 × 6.9 = 62.1 mm
Length = 110.4 mm and width = 62.1 mm
B) area of screen is;
A = length × width
A = 110.4 × 62.1
A = 6855.84 mm²
C) We are told that the aspect ratio is now 18.5:9.
Thus;
length = 18.5x
width = 9x
Thus;
(18.5x)² + (9x²)] = 127²
342.25x² + 81x² = 16129
423.25x² = 16129
x² = 16129/423.25
x = √(16129/423.25)
x = 6.2
length = 18.5x = 18.5 × 6.2 = 114.7 mm
width = 9x = 9 × 6.2 = 55.8 mm
Area = 114.7 × 55.8 = 6400.26 mm²
D) Screen with aspect ratio of 16:9 is bigger
Answer:
It goes from smallest to largest value
Step-by-step explanation: hope this helps :)
Answer:
1 2/5
Step-by-step explanation:
Answer:
340 pounds of wool
Step-by-step explanation:
If we take the estimate of 25 pounds for 5 sheep, you can guess that there is 5 pounds from each sheep. So, 5×68=340
Answer:
A volcano ejected with an initial velocity of 304 feet per second.
The height in feet is given by the equation H=-16t^2+ 304t where t is the time in seconds.
We will use the equation that traces the path of the projectile to determine the following information:
1) The time it takes the projectile to reach its maximum height (using the vertex formula: t=-b/2a)
The equation; H = -16t^2 + 304t, a=-16; b=304
t = -304/2°(-16)
t = 9.5 sec to reach max height
2) The maximum height of the projectile (use the result from part 1 to find the maximum height of the projectile)
t = 9.5
H = -16(9.5^2) + 304(9.5)
h = = -1444 + 2888
h = 1444 ft is the max height
3) Find the time it takes the projectile to return to the ground. Assume that the projectile starts at height H=0.
-16t^2 + 304t = 0
factor out -16t
-16t(t - 19) = 0
t = 19 sec to reach the ground
Step-by-step explanation:
