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3 years ago

What distance was an object moved by a force of 40 N if the work was 600 joules

Physics

2 answers:

rewona [7]3 years ago

8 0

Answer:

15 Meters

Explanation:

Westkost [7]3 years ago

6 0

If a force of 40 N does 600 joules of work, then it must have been applied continuously through a distance of (600/40) = 15 meters .

We can't tell how far the object ultimately moved, because we don't know
what other forces may have been acting on it. If there were NO other forces,
then it just kept going, even after the 40-N force stopped, with the same
600 joules of kinetic energy that it got from the work that the force did.

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A hollow sphere of radius 0.200 m, with rotational inertia I = 0.0484 kg·m2 about a line through its center of mass, rolls witho

d1i1m1o1n [39]

Answer:

Part a)

$KE_r = 8 J$

Part b)

v = 3.64 m/s

Part c)

$KE_f = 12.7 J$

Part d)

$v = 2.9 m/s$

Explanation:

As we know that moment of inertia of hollow sphere is given as

$I = \frac{2}{3}mR^2$

here we know that

$I = 0.0484 kg m^2$

R = 0.200 m

now we have

$0.0484 = \frac{2}{3}m(0.200)^2$

$m = 1.815 kg$

now we know that total Kinetic energy is given as

$KE = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2$

$KE = \frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{R})^2$

$20 = \frac{1}{2}(1.815)v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2$

$20 = 1.5125 v^2$

$v = 3.64 m/s$

Part a)

Now initial rotational kinetic energy is given as

$KE_r = \frac{1}{2}I(\frac{v}{R})^2$

$KE_r = \frac{1}{2}(0.0484)(\frac{3.64}{0.200})^2$

$KE_r = 8 J$

Part b)

speed of the sphere is given as

v = 3.64 m/s

Part c)

By energy conservation of the rolling sphere we can say

$mgh = (KE_i) - KE_f$

$1.815(9.8)(0.900sin27.1) = 20- KE_f$

$7.30 = 20 - KE_f$

$KE_f = 12.7 J$

Part d)

Now we know that

$\frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{r})^2 = 12.7$

$\frac{1}{2}(1.815) v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2 = 12.7$

$1.5125 v^2 = 12.7$

$v = 2.9 m/s$

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3 years ago

What would be the average fixed cost per unit at an activity level of 5,200 units? assume that this level of activity is within

Vitek1552 [10]

The average fixed cost per unit at an activity level of 5,200 units is $6.00.

<h3>What is the average fixed cost?</h3>

The average fixed cost (AFC) is fixed cost that does not change with the change in the number of goods and services produced by a company. To put it in a nutshell, average fixed cost (AFC) is the fixed cost per unit and is calculated by dividing the total fixed cost by output level.

Since no cost is fixed for a long time, average fixed cost is only for a short run. When units of production increase, the average fixed cost per unit decreases. Similarly, when the business produces less units, average cost increases per unit.

However, only one unit, mostly capital, is fixed. Examples of average fixed cost are the salaries of permanent employees, mortgage payment on machinery and plant, rent, more.

Average Fixed Cost Formula:

AFC = Total fixed cost/Output (Q)

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2 years ago

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velikii [3]

Answer:

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So true might not be the correct answer. The question is very complex and does not lend itself to a simple True/ False answer.

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