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FinnZ [79.3K]
3 years ago
13

What distance was an object moved by a force of 40 N if the work was 600 joules

Physics
2 answers:
rewona [7]3 years ago
8 0

Answer:

15 Meters

Explanation:

Westkost [7]3 years ago
6 0

If a force of 40 N does 600 joules of work, then it must have been applied continuously through a distance of  (600/40) = 15 meters .

We can't tell how far the object ultimately moved, because we don't know
what other forces may have been acting on it.  If there were NO other forces,
then it just kept going, even after the 40-N force stopped, with the same
600 joules of kinetic energy that it got from the work that the force did.


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What can the arrow in a chemical reaction be translated to mean? Check all that apply.
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3 years ago
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Microwave ovens heat food through the process of A) COnduction B) Convection C) Radiation D)Stratification
Andru [333]

Answer:

\huge\boxed{Radiation}

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A rock of mass 0.340 kg is spun horizontally at the end of a wire that has a diameter of 1.00 mm. If the wire gets stretched by
borishaifa [10]

Answer:

Y = 78.13 x 10⁹ Pa = 78.13 GPa

Explanation:

First we will find the centripetal force acting on the wire as follows:

F = mv²/r

where,

F = Force = ?

m = mass of rock = 0.34 kg

v = speed = 19 m/s

r = length of wire

Therefore,

F = (0.34)(19)²/r

F = 122.74/r  

now, we find cross-sectional area of wire:

A = πd²/4

where,

A = Area = ?

d = diameter of wire = 1 mm = 0.001 m

Therefore,

A = π(0.001)²/4

A = 7.85 x 10⁻⁷ m²

Now, we calculate the stress on wire:

Stress = F/A

Stress = (122.74/r)/(7.85 x 10⁻⁷)

Stress = 1.56 x 10⁸/r

Now, we calculate strain:

Strain = Δr/r

where,

Δr = stretch in length = 2 mm = 0.002 m

Therefore,

Strain = 0.002/r

now, for Young's modulus (Y):

Y = Stress/Strain

Y = (1.56 x 10⁸/r)/(0.002/r)

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