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Dennis_Churaev [7]
3 years ago
11

In a four stroke engine, the piston compresses the gas mixture during the ______ stroke.

Physics
1 answer:
barxatty [35]3 years ago
5 0

Answer : Compression / Power

Explanation : In a four stroke engine, the piston compresses the gas mixture during the power / compression stroke.

In the second stage of compression stroke, the stroke begins at bottom dead center, or just at the end of the suction stroke, and ends at top dead center.

In this type of stroke, the piston usually compresses the air-fuel mixture in preparation for ignition during the power stroke.

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Two blocks with masses 1 and 2 are connected by a massless string that passes over a massless pulley as shown. 1 has a mass of 2
Bess [88]

Answer:

The acceleration of M_2 is  a =  0.7156 m/s^2

Explanation:

From the question we are told that

    The mass of first block is  M_1 =  2.25 \ kg

    The angle of inclination of first block is  \theta _1 =  43.5^o

    The coefficient of kinetic friction of the first block is  \mu_1  = 0.205

      The mass of the second block is  M_2 = 5.45 \ kg

     The angle of inclination of the second block is  \theta _2 =  32.5^o

      The coefficient of kinetic friction of the second block is \mu _2 = 0.105

The acceleration of M_1 \ and\  M_2 are same

The force acting on the mass M_1 is mathematically represented as

     F_1 = T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1

=> M_1 a = T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1

Where T is the tension on the rope

The force acting on the mass M_2 is mathematically represented as    

  F_2 =  M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

   M_2 a =  M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

At equilibrium

  F_1 =  F_2

So

 T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1 =M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

making a the subject of the formula

    a =  \frac{M_2 g sin \theta_2 - M_1 g sin \theta_1 - \mu_1 M_1g cos \theta - \mu_2 M_2 g cos \theta_2 }{M_1 +M_2}

substituting values a =  \frac{(5.45) (9.8) sin (32.5) - (2.25) (9.8) sin (43.5) - (0.205)*(2.25) *9.8cos (43.5) - (0.105)*(5.45) *(9.8) cos(32.5) }{2.25 +5.45}

    => a =  0.7156 m/s^2

     

3 0
4 years ago
What is the power of 10 when 157,821 is written in scientific notation?
vlabodo [156]

Answer:

The power of 10 in the given value is 5.

Explanation:

scientific notation is expressed in the decimal form. That means always written in the power of 10 form. The decimal place is put after 1 digit.

3 0
4 years ago
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One way to conserve energy is to replace incandescent light bulbs with compact fluorescent bulbs. The fluorescent bulb typically
NemiM [27]

Answer:

     cos to = $ 24

Explanation:

When replacing the bulb only 25% of the energy is used, therefore

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now we can calculate the cost using a direct proportion rule.

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4 0
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Suppose a drinking straw is in a glass of water. Someone blows air across the top of the straw. The water level in the straw ___
enyata [817]
The answer is A. drops! Suppose a drinking straw is in a glass of water. Someone blows air across the top of the straw. The water level in the straw will be drops. 

Hope it helped!
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4 years ago
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Trava [24]

The statement “All of the earth's life and weather exists within the stratosphere” is false. The answer is letter B. The answer is the troposphere. The first layer, troposphere, is where we are able to do most of our activities. This is where we can see the formation of clouds, the production of rain, hail, snow and other weather phenomenon. Also, this layer is where the greatest amount of air pressure because most of the molecules of air are in this area. Like us, air has also mass and the pressure is brought down by the earth’s gravity causing an increase in weight exerted on you as you descend lower into the atmosphere. So, as you enter into the other layers of atmosphere above the troposphere, the air pressure starts to decrease. <span>Below the atmosphere is the hydrosphere. This is where all liquid forms are located. And since the seawater has a greater mass than air, it has the greatest pressure. </span>

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