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3 years ago

Given: m∠ACB = m∠ABCProve: ∠XCA = ∠YBA

Mathematics

1 answer:

klio [65]3 years ago

4 0

Answer:

Given that <ACB is congruent to <ABC we can infer that the triangle formed is an isosceles triangle. If B and C are both congruent and the distance from c and x and b and y are also congruent than the angles are congruent.

Step-by-step explanation:

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Find the measure of each angle.<br><br> m∠BAC=<br> m∠CAD=

NARA [144]

i dont have much time to go through all the work but i can tell you that since its a 90 degree angle, your equation would be 90=15x-2+7x+4. Once you get the value of X plug that into each of the equations. For example if your x value was 2 you would do 15(2)-2. Thats just an example.

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3 years ago

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9.Which of the following are used to represent unknown quantities in algebra? A) Upper case letters B) Lower case letters C) Onl

bearhunter [10]

Answer:

B - Lower case letters

Step-by-step explanation:

In algebra, unknown quantities are usually represented as lower-case letters like $x, y, i, j, k$ etc.

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3 years ago

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Find the volumes of the solids generated by revolving the triangle with vertices (2, 2), (2, 6), and (5, 6) about a) the x-a

Vesna [10]

About the $x$ -axis (washer method):

$\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}$

About the $y$ -axis (shell method):

$\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}$

About $x=7$ (shell method):

$\displaystyle2\pi\int_2^5(7-x)\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5(35-12x+x^2)\,\mathrm dx=\boxed{48\pi}$

About $y=2$ (washer method):

$\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}$

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4 years ago

4 people are on the team. Members will be chosen randomly to serve as chairperson, treasurer, secretary, or timekeeper . Noor is

aliina [53]

Answer:

Step-by-step explanation:

Given that four people are on the team. Members will be chosen randomly to serve as chairperson, treasurer, secretary, or timekeeper

Since one person cannot serve two posts we have total number of ways

= 4(3)(2)(1) = 24

If Noor is chair person and Qu treasurer then remaining 2 can take two posts in 2 different ways

So probability that Noor is selected to be chairperson and Qu is selected to be treasurer

=favourable outcomes/total outcomes

= $\frac{2}{24} \\=0.083$

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4 years ago

!! AP CALCULUS AB !!<br> find the limit of [(secx*sinx) + (cscx*cosx)]/(3secx) as x approaches 3pi/2

uysha [10]

$f(x)= \frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}}$

$\frac{\frac{\sin{x}}{\cos{x}}+\frac{\cos{x}}{\sin{x}}}{3\sec{x}} \implies \\ \frac{\sin^2{x}+\cos^2{x}}{\sin{x}\cos{x}}\frac{\cos{x}}{3}\implies \\\frac{1}{\sin{x}\cos{x}}*\frac{\cos{x}}{3}\implies \\ \frac{1}{3\sin{x}}$

So,

$\lim_{x \rightarrow \frac{3\pi}{2}}{f(x)=f(\frac{3\pi}{2})=\frac{1}{3\sin{\frac{3\pi}{2}}}=-\frac{1}{3}$

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3 years ago