It is easier to understand the problem if you create a number based on the criteria and then perform the computations. I am going to choose: 111 22 33 4
There are 10 options for the first "1" and only 1 option for the other two 1's
There are 9 remaining options for the first "2" and only 1 option for the other 2
There are 8 remaining options for the first "3" and only 1 option for the other 3
There are 7 remaining options for the "4"
10 x 1 x 1 x 9 x 1 x 8 x 1 x 7
10 x 9 x 8 x 7 = 5,040
Answer: 5,040
10 time as much of something is basically just multiplication, so all you have do is multiply 60x10 which equals 600 :)
Answer:
Question 13: 90, Question 14: y = 
, Question 15: x = 
, Question 16: y = 
.
Step-by-step explanation:
Is there more to the question? If not I say D
