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3 years ago

Find the length of CU, the triangles are similar.

Mathematics

1 answer:

Otrada [13]3 years ago

3 0

Answer:

CU = 117

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{WC}{WU}$ = $\frac{CD}{UV}$

substituting in values to the ratios

$\frac{26}{36x-1}$ = $\frac{24}{132}$ ( cross- multiply )

24(36x - 1) = 3432 ( divide both sides by 24 )

36x - 1 = 143 ( add 1 to both sides )

36x = 144 ( divide both sides by 36 )

x = 4

CU = 36x - 1 - 26 = (36 × 4) - 27 = 144 - 27 = 117

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$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

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On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

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Find the polynomial function in standard form that has the zeros listed. i and -i

fgiga [73]

The polynomial function in standard form that has the zeros listed. i and -i is x² +1 = 0.

<h3>What is polynomial function?</h3>

A quadratic, cubic, quartic, and other functions involving only non-negative integer powers of x are examples of polynomial functions.

The values of x that fulfil the formula f(x) = 0 are the zeros of a polynomial. The polynomial's zeros are the x values for which the function's value, f(x), equals zero in this case. The degree of the equation f(x) = 0 determines how many zeros a polynomial has.

Calculation for the polynomial function-

The general two degree/quadratic equation is given by-

ax² + bx + c = 0

Where a ≠ 0

If the two roots of the equation are x1 and x2.

Then the relation between roots and coefficients of the polynomial are -

The sum of the roots = (- coefficient of x)/(coefficient of x²)

x1 + x2 = (-b)/a

The multiplication of the roots = constant/coefficient of x²

x1.x2 = c/a

From the above two relation the general equation can be written as-

x² -(x1 - x2)x + x1.x2 = 0

Lets say x1 = i and x2 = -i

Substitute the values of x1 and x2 in the general equation

x² -(i - i)x + (i).(-i) = 0

x² - i ² = 0

x² + 1 = 0

Therefore, the polynomial function in standard form that has the zeros listed. i and -i is x² + 1 = 0.

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