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creativ13 [48]
3 years ago
14

En la etiqueta de un bote de fabada de 350 g, leemos que su aporte energético es de 1630 kj por cada 100 g de producto a) La can

tidad de fabada que tiene que comer un hombre si su necesidad energética diaria es 2500 kj para sobrevivir b) El aporte calórico del bote de fabada en calorías
Physics
1 answer:
fredd [130]3 years ago
6 0

Answer:

(a) 153.37 g

(b) 5705 kJ

Explanation:

(a) To find the amount of bean needed by a man you first calculate the equivalence in beans to 2500kJ

2500kJ*\frac{100g}{1630kJ}=153.37\ g

Thus, 153.37 g has the energy needed by a man that needs 200kJ per day.

(b) The amount of energy per pot of bean is given by:

E=350g*\frac{1630kJ}{100g}\\\\E=5705\ kJ

Thus, the energy is 5705kJ

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olga2289 [7]
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7 0
3 years ago
a. What is the peak wavelength for AM0? What temperature T corresponds to this peak wavelength for a blackbody source? Assuming
atroni [7]

Answer:

A) T = 5510 K , B)   I = 5,226 10⁷ W / m² , C)   I₂ = 1128 W / m²

Explanation:

A) The mass of air is defined as the ratio between the shortest path that sunlight must pass to reach the planet's surface and the length of the beam, is called AM

      Am = 1 / cos θ

The AM0 value corresponds to solar radiation in the outer part of the Earth's atmosphere.

The peak of this emission is the peak that emitted from the sun

       λ = 526 nm

To find the temperature that corresponds to this emission we use the Wien displacement law

       λ T = 2,898 10⁻³

      T = 2,898 10⁻³ / 526 10⁻⁹

      T = 5510 K

i) The radiance on the surface of the sun is

           I = P / A

We can calculate the potency by Stefan's law, for a black body

         P = σ A e T⁴

         P / A = σ e T⁴

The σ constant is value 5,670 10⁻⁸ W / m²K⁴, we will assume that the Sun emits as a black body, so e = 1

            I = sig T⁴

            I = 5,670 10⁻⁸  5510⁴

            I = 5,226 10⁷ W / m²

ii) the irradiation at a distance of 1 ua (1,496 1011 m)

Let's use the relationship

           P = I A

           I₁ A₁ = I₂ A₂

           I₂ = I₁ A₁ / A₂

 

The area of ​​a sphere is

          A = 4π R²

Let's replace

         I₂ = I₁ (r₁ / r₂)²

  Index 1 corresponds to the sun and the index to Earth that is an astronomical unit

        r₁ = 6.96 10⁸m        (Sun radius)

        r₂ = 1,498 1011 m    (Earth-Sun distance)

Calculous

       I₂ = 5,226 10⁷ (6.96 10⁸ / 1,498 10¹¹)²

       I₂ = 1.1281 10³ W / m²

       I₂ = 1128 W / m²

8 0
3 years ago
A girl standing upright exerts a pressure of 15000 N/m2 on the floor. Given that the total area of contact of shoes and the floo
lapo4ka [179]

Explanation:

F=15000/0.02

=300N

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=30 000Pa/30 000Nm^-2

in another way=15000×2

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