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1 year ago

7

If the resultant force acting on a 2.0 kg object is equal to (3.0î + 4.0ĵ) N, what is the change in kinetic energy as the object

moves from (7.0î – 8.0ĵ) m to (11.0î – 5.0ĵ) m?

1 answer:

12345 [234]1 year ago

3 0

Answer:

ΔK = 24 joules.

Explanation:

Δ $K =$ Work done on the object

Work is equal to the dot product of force supplied and the displacement of the object.

$W = F$ * Δ $s$

Δ $s$ can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δ $s$ = (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).

This gives us

$W = < 3, 4 >$ * $< 4, 3 >$ = $(3*4)+(4*3)$ = $24$ J

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