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3 years ago

13

A propane tank is filled with a mixture of liquid and vapor propane. Can the contents of this tank be considered a pure substanc

e? Explain it.

1 answer:

grin007 [14]3 years ago

3 0

Yes because both contents would be considered pure substances since they share phases that contain the same chemical composition.

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What are the benefits and harms of protists? WILL GIVE BRAINLIEST FOR THE PERFECT ANSWER

alina1380 [7]

Answer:

<em>Well, Many protists are harmful to humans, other animals and plants because they cause diseases and crop failures. However, some protists are actually beneficial to other creatures and are used by humans for various purposes. Plant-like protists produce almost one-half of the oxygen on the planet through photosynthesis. Other protists decompose and recycle nutrients that humans need to live. For example, medicines made from protists are used in treatment of high blood pressure, digestion problems, ulcers, and arthritis. Hope That Helps!</em>

<em>From ~Itsbrazts~. Have a Great Day!</em>

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3 years ago

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A balloon is rising vertically upwards at a velocity of 10m/s. When it is at a height of 45m from the ground, a parachute bails

harina [27]

(a) 30.9 m

Let's analyze the motion of the parachutist. Its vertical position above the ground is given by

$y=h+ut+\frac{1}{2}gt^2$

where

h = 45 m is the initial height

u = 10 m/s is the initial velocity (upward)

t is the time

g = -9.8 m/s^2 is the acceleration of gravity (downward)

Substituting t=3 s , we find the height of the parachutist when it opens the parachute:

$y=45 m+(10 m/s)(3 s)+\frac{1}{2}(-9.8 m/s^2)(3 s)^2=30.9 m$

(b) 44.1 m

Here we have to find first the height of the balloon 3 seconds after the parachutist has jumped off from it. The vertical position of the balloon is given by

y = h + ut

where

h = 45 m is the initial height

u = 10 m/s is the initial velocity (upward)

t is the time

Substituting t = 3 s, we find

y = 45 m + (10 m/s)(3 s) = 75 m

So the distance between the balloon and the parachutist after 3 s is

d = 75 m - 30.9 m = 44.1 m

(c) 8.2 m/s downward

The velocity of the parachutist at the moment he opens the parachute is:

v = u +gt

where

u = 10 m/s is the initial velocity (upward)

t is the time

g = -9.8 m/s^2 is the acceleration of gravity (downward)

Substituting t = 3 s,

v = 10 m/s + (-9.8 m/s^2)(3 s)= -19.4 m/s

where the negative sign means it is downward

After t=3 s, the parachutist open the parachute and it starts moving with a deceleration of

a =+5 m/s^2

where we put a positive sign since this time the acceleration is upward.

The total distance he still has to cover till the ground is

d = 30.9 m

So we can find the final velocity by using

$v^2-u^2 = 2ad$

where this time we have u = 19.4 m/s as initial velocity. Taking the downward direction as positive, the deceleration must be considered as negative:

a = -5 m/s^2

Solving for v,

$v=\sqrt{u^2 +2ad}=\sqrt{(19.4 m/s)^2+2(-5 m/s^2)(30.9 m)}=8.2 m/s$

(d) 5.24 s

We can find the duration of the second part of the motion of the parachutist (after he has opened the parachute) by using

$a=\frac{v-u}{t}$

where

a = -5 m/s^2 is the deceleration

v = 8.2 m/s is the final velocity

u = 19.4 m/s is the initial velocity

t is the time

Solving for t, we find

$t=\frac{v-u}{a}=\frac{8.2 m/s-19.4 m/s}{-5 m/s^2}=2.24 s$

And added to the 3 seconds between the instant of the jump and the moment he opens the parachute, the total time is

t = 3 s + 2.24 s = 5.24 s

8 0

3 years ago

Two point charges are separated by 6 cm. The attractive force between them is 20 N. Find the force between them when they are se

Scorpion4ik [409]

Answer:

5 N

Explanation:

$F_1$ = 20 N

$r_1$ = 6 cm

$r_2$ = 12 cm

k = Coulomb constat

q = Charge

$\dfrac{F_1}{F_2}=\dfrac{\dfrac{kq_1q_2}{r_1^2}}{\dfrac{kq_2q_2}{r_2^2}}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{12^2}{6^2}\\\Rightarrow \dfrac{F_1}{F_2}=4\\\Rightarrow F_2=\dfrac{F_1}{4}\\\Rightarrow F_2=\dfrac{20}{4}\\\Rightarrow F_2=5\ N$

The force is 5 N

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3 years ago

What is kelvin scale?

Darina [25.2K]

<span>a scale of temperature with absolute zero as zero, and the triple point of water as exactly 273.16 degrees.</span>

4 0

4 years ago

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_________ acceleration occurs when an object speeds up.

Angelina_Jolie [31]

Positive acceleration occurs when an object speeds up.

Explanation:

Acceleration is the rate of change in velocity per unit time:

$a=\frac{\Delta v}{\Delta t}$

where $\Delta v$ is the change in velocity while $\Delta t$ is the time interval. From the formula, we can understand that when $\Delta v$ is positive, so when the object is speeding up, the acceleration is positive; on the contrary, when $\Delta v$ is negative (so, when the object is slowing down), the acceleration is negative.

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3 years ago

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