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4 years ago

When given angle measures of 25°, 65°, and

Mathematics

1 answer:

Blababa [14]4 years ago

6 0

You first add all the angles together.

25 + 65 + 90 = 180°

The total angle measurement of a triangle is 180°. Therefore, it is possible to only make one triangle.

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Write the slope-intercept form of the equation for the line. a. y=-8/7x+3/2 b.y= -3/2x+7/8 c.y=-7/8x-3/2 d.y=7/8x+3/2 Write the

fgiga [73]

Answer:

Step-by-step explanation:

(-4,2) ; (4,-5)

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-5-2}{4-[-4]}\\\\=\frac{-7}{4+4}\\\\=\frac{-7}{8}$

m = -7/8 ; (-4,2)

equation: y - y1 = m(x - x1)

$y-2=\frac{-7}{8}(x-[-4])\\\\y-2=\frac{-7}{8}(x+4)\\\\y-2=\frac{-7}{8}x +\frac{-7}{8}*4\\\\y=\frac{-7}{8}x-\frac{7}{2}+2\\\\y=\frac{-7}{8}x-\frac{7}{2}+\frac{4}{2}\\\\y=\frac{-7}{8}x-\frac{3}{2}\\$

5 0

3 years ago

6.7 more than the product of 5 and n

Daniel [21]

The product of 5 and n : 5(n) 6.7 more : +6.7 5n + 6.7 is your expression Hope this helps

6 0

4 years ago

Which reason justifies the last step in a proof that ΔEDG≌ΔADC?

Alja [10]

It is side angle side postulate
fd is congruet to db
ed is congruent to da
and vertical angles theorem

5 0

4 years ago

Consider the following. (See attachment)

Furkat [3]

Answer:

Area: 16

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Calculus

Derivatives

Derivative Notation

Integrals - Area under the curve

Trig Integration

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 8sin(x) + sin(8x)$

$\displaystyle y = 0$

Bounds of Integration: 0 ≤ x ≤ π

Step 2: Find Area Pt. 1

Set up integral: $\displaystyle A = \int\limits^{\pi}_0 {[8sin(x) + sin(8x)]} \, dx$
Rewrite integral [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{\pi}_0 {8sin(x)} \, dx + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 8\int\limits^{\pi}_0 {sin(x)} \, dx + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Integrate [Trig Integration]: $\displaystyle A = 8[-cos(x)] \bigg| \limits^{\pi}_0 + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = 8(2) + \int\limits^{\pi}_0 {sin(8x)} \, dx$
Multiply: $\displaystyle A = 16 + \int\limits^{\pi}_0 {sin(8x)} \, dx$

Step 3: Identify Variables

Identify variables for u-substitution.

u = 8x

du = 8dx

Step 4: Find Area Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 16 + \frac{1}{8}\int\limits^{\pi}_0 {8sin(8x)} \, dx$
[Integral] U-Substitution: $\displaystyle A = 16 + \frac{1}{8}\int\limits^{8\pi}_0 {sin(u)} \, du$
[Integral] Integrate [Trig Integration]: $\displaystyle A = 16 + \frac{1}{8}[-cos(u)] \bigg| \limits^{8\pi}_0$
[Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = 16 + \frac{1}{8}(0)$
Simplify: $\displaystyle A = 16$