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timurjin [86]
4 years ago
13

What is the pattern in the values as the exponents increase? Powers of 2 Value 2 Superscript negative 5 StartFraction 1 Over 32

EndFraction 2 Superscript negative 4 StartFraction 1 Over 16 EndFraction 2 Superscript negative 3 StartFraction 1 Over 8 EndFraction 2 Superscript negative 2 One-fourth 2 Superscript negative 1 One-half 2 Superscript 0 1 add StartFraction 1 Over 16 EndFraction to the previous value subtract StartFraction 1 Over 16 EndFraction from the previous value divide the previous value by 2 multiply the previous value by 2 Please

Mathematics
2 answers:
romanna [79]4 years ago
7 0

Answer:

Step-by-step explanation:

proof

Tatiana [17]4 years ago
6 0

Answer:

(D)Multiply the previous value by 2

Step-by-step explanation:

\left|\begin{array}{c|c}$Powers of 2&Value\\2^{-5}&\frac{1}{32}\\\\2^{-4}&\frac{1}{16}\\\\2^{-3}&\frac{1}{8}\\\\2^{-2}&\frac{1}{4}\\\\ 2^{-1}&\frac{1}{2}\\\\2^{0}&1\end{array}\right|

From the given table, we observe that the negative power of 2 reduces by 1 at each step.

2^{-5}X2=2^{-4}\\2^{-4}X2=2^{-3}\\2^{-3}X2=2^{-2}

Therefore, as the exponents increase, we multiply the previous value by 2 to obtain the next value.

The correct option is D.

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netineya [11]

Answer:

I want to say A)

Step-by-step explanation:

5 0
3 years ago
6-4x=(3-x)<br> A) -2<br> B) 2<br> C) all real, numbers<br> D) no solution
Semmy [17]
6 - 4x = (3 - x)

Subtract 6 from both sides, as well as adding x to both sides.

-4x + x = 3 - 6

Add like terms.

-3x = -3

Divide both sides by -3.

x = 1

So, your answer is c) All real, numbers because all of the other answer choices are wrong. 

We know this because a) and b) are incorrect. To know if they are incorrect, you just plug in the numbers. When 2 and -2 are plugged into the equation, it is incorrect. So, you solve the equation, and you now know that it is not D) because there is a solution. 

So, once again, your answer is C.

~Hope I helped!~

6 0
3 years ago
Read 2 more answers
Write a linear inequality in two variables that has (-1, 3) as a solution but does not have (4,0) as a solution.
Stels [109]

Answer:  y ≤ -x + 2

<u>Step-by-step explanation:</u>

There are an infinite number of possible solutions.

Plot the two points, draw any line between them such that the two points are NOT connected, then choose the inequality symbol that shades (-1, 3).

Here is one solution that satisfies the requirements.   y ≤ -x + 2

Here is another: y < -x + 3

And another: y > x + 3

And one more: y ≥ x + 4

3 0
3 years ago
7:11 and 21:33 yes or no
grandymaker [24]
Yes!! They both are equivalent.....
7 0
3 years ago
A class of 33 students elected a class treasurer. there were 111votes for candidate a and 15 votes for candidate
Advocard [28]

Since 111 is greater than 33, I will assume that you meant 11 votes for a candidate. Also, assuming that each student can vote only once, the answer would be

11/33 x 100=33.333333...

About 33.333 of the voters voted for candidate a.

3 0
3 years ago
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