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labwork [276]
3 years ago
7

A survey asked a group of students to list their eye color. The results of the survey are shown in the graph.

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0

Answer:

b?

Step-by-step explanation:

drek231 [11]3 years ago
3 0
I think the answer is b
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A new test is developed to test for a certain allergy, giving "positive" or "negative" results to indicate that a person does or
notsponge [240]

Answer:

  1. the first blank is 82, the second blank is 8,910. I got that third blank wrong and it should be 7.1 I think. and the last block is should not. to find the third box all you need to do is:
  2. 82+990=1,072 then divide 82 by 1,072 and round to the nearest tenth
5 0
3 years ago
Answer truthfully pleaseeeeee
alexandr1967 [171]

Answer:

1/4

Step-by-step explanation:

i took the quiz

3 0
3 years ago
3.006 rounded to the nearest tenth
Ann [662]
3.006 rounded to the nearest tenth is 3.0. This is due to the fact that the 6 rounded up will mean that the current 0 becomes 1, but this will not be carried to the tenth when rounding up.
3 0
3 years ago
Read 2 more answers
Solve this system of linear equations. -14x + 11y = 23 7x - 3y = 37 <br> x=? y=?
lesya692 [45]
<span> -14x + 11y = 23
+2(7x - 3y = 37)
----------------------
   0 + 5y = 97
y  = 97/5
y = 19.4

7x - 3(19.4) = 37
7x - 58.2 = 37
7x = 37 + 58.2
7x = 95.2
x = 95.2/7
x = 13.6

Check

-14(13.6) + 11(19.4) = 23
-190.4 + 213.4 = 23
</span>
3 0
3 years ago
I really am confused on how to write a proof.
kvasek [131]

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

\begin{gathered} AB=CD \\ BC=AD \end{gathered}

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

\begin{gathered} AE=CE \\ BE=DE \end{gathered}

Hence Proved.

8 0
1 year ago
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