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7nadin3 [17]
4 years ago
13

Make a list of the 2- digit numbers

Mathematics
2 answers:
MrRissso [65]4 years ago
5 0
12
13
78
97
65
90
70
these are numbers with 2 digits
Zinaida [17]4 years ago
3 0
10,11, 12, 13, 14, 15, 16, 17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,
33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,
57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,78,79,80,81,
82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99
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5[×-2] what is the distributive property
iogann1982 [59]

Answer:

5x - 10

Step-by-step explanation:

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Graph a line with a slope of 5 that contains the point (-2,4). <br><br>Khan Academy <br>​
weeeeeb [17]

Answer:

Graph the point (-2, 4) and then use rise over run (Up 2 and right 5)

Step-by-step explanation:

y - y1 = m(x - x1)

y - 4 = 2/5(x + 2)

y - 4 = 2/5x + 4/5

y = 2/5x + 24/5

4 0
3 years ago
I need help please??!!!
vaieri [72.5K]

Answer:

∛343,8,√108

since ∛343 = 7

8 is greater than 7 so 8>∛343

and √108 = approx 10

so 7<8<10

6 0
3 years ago
Which list shows fraction that ALWAYS result in a terminating decimal for values of n &gt; 0? A) 1/11, 1/121, 1/1331 . . . , 1/1
Alla [95]

Answer:

B) 1/10, 1/100, 1/1000 . . . , 1/10n

Step-by-step explanation:

Comparing all the options given:

A) 1/11, 1/121, 1/1331 . . . , 1/11n

Finding the decimal of the first term,

1/11 = 0.0909090 (never ending decimal place)

B) 1/10, 1/100, 1/1000 . . . , 1/10n

Finding the decimal of the first term,

1/10 = 0.01 (ended decimal place)

C) 1/6, 1/36, 1/126 . . . , 1/6n

Finding the decimal of the first term,

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Finding the decimal of the first term,

1/3 = 0.33333333 (never ending decimal place)

7 0
3 years ago
Read 2 more answers
Five friends have access to a chat room. Is it possible to determine who is chattingif the following information is known? Eithe
fenix001 [56]

Answer:

Kevin and Vijay are chatting

Step-by-step explanation:

Consider: Kevin=k

Heather=h

Randyor=v

Vijay=v

Abby=a

The values or the variables can be =o if they are not chatting and =1 if they arre chatting, then:

k+h>=1

v+r=1

a=r

v=k

if h=1 then a=1 and k=1, then as a=r, r=1 and as v=k, v=1, but then v+r=2, which is not possible because v+r=, then we can fisrt conclude than h=0.

.As k+h>=1, and h=0, then k=1. As k=v, then v=1.  

As v+r=1, and v=1, then r=0. As r=a, a=0

So in conclusion, a=0, r=0, v=1, k=1 and h=0, so Kevin and Vijay are chatting

4 0
3 years ago
Read 2 more answers
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