Answer:
x^3-x^2+1
Step-by-step explanation:
u(x)=x^5-x^4+x^2
v(x)=-x^2
(u/v)(x) = (x^5-x^4+x^2) /x^2
= (x^5/x^2) - (x^4 /x^2) +(x^2/x^2)
= x^(5-2) - x ^(4-2)+ x ^(2-2)
=x^3-x^2+1
Closer to 2. If you round it, because the number after the 2 is less than 5 you round it down so it's closer to 2
Can't see it the equation is to blurry.
The correct answer is " (1) Reflect ABC across the x-axis and call this new triangle A'B'C'. (2) Translate A'B'C' 2 units right and 6 units up so that its image is A''B''C''. "
It is assumed that the points are
A in ABC is (1,9), B in ABC is (3,12), and C in ABC is (4,4).
A'' in A''B''C'' is (3,-3), B'' in A''B''C'' is (5,-6), and C'' in A''B''C'' is (6,2).
Both triangles are congruent. Since they are congruent, there are no contractions nor dilations occured. After rotating clockwise, we get A"C"B". So we need to reflect it to get A"B"C"
hope this helped :D
