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Goshia [24]
3 years ago
9

(08.01)Consider the following system of equations:

Mathematics
1 answer:
Anika [276]3 years ago
5 0

Lines y = −2x + 3 and y = 3x – 5 intersect the x-axis.

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Because of the rainy season, the depth in a pond increases 3% each week. Before the rainy season started, the pond was 10 feet d
Dafna11 [192]

It's not perfectly clear, but you seem to be saying that each week, the
pond becomes 3% deeper than it was THE PREVIOUS WEEK.

If I'm reading that correctly, then the pond is 10-ft deep when the rainy
season begins, and after 'x' weeks later, the depth is

                     D = 10 (1.03)^x            feet.

After 8 weeks, the depth is        D = 10 (1.03)⁸  =  12.67 feet .

                         rounded to the nearest foot,  D = 13 ft.

                

7 0
3 years ago
Read 2 more answers
HELP I WILL GIVE 5 POINTS TO WHOM EVER CAN ANSWER THESE LAST 2 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
vodka [1.7K]
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important



6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of  2 perfect squares
(2d)(d-1)(d+1)(3d+2)






77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
7 0
3 years ago
How many factors of 2 are there in 2³? answers> 1 2 3 5​
algol [13]

Answer:

2

Step-by-step explanation:

2^3= 2*2*2

factors of 8= 1,2,4,8

factors of 2= 1,2

6 0
3 years ago
|(a + b)x + y = 4<br> |x + (a - b)y + 10
leonid [27]

I don't know the answer but try using PEMDAS. (Parentheses, Exponents, Multiplication, Division, Addition, and then Subtraction)

4 0
3 years ago
Two factory plants are making TV panels. Yesterday, Plant A produced 16,000 panels. Five percent of the panels from Plant A and
weeeeeb [17]

Answer:

Number of panels produced by Plant B is 8,000.

Step-by-step explanation:

The number of panels produced by Plant A  = 16,000

The number of defective panels from A = 5%

Now, 5% of 16,000 = \frac{5}{100}  \times 16,000 = 800

So, out of  16,000 panels produced by pant A , 800 are defective. .. (1)

Let us assume number of panels produced by Plant B  = m

The number of defective panels from B = 2%

Now, 2% of m = \frac{2}{100}  \times m = 0.02 m

So, out of total m panels produced by pant B , 0.02 m are defective. .. (2)

Now, total panels produced over all = Panels by A  + Panels by B

= 16,000 + m

The percentage of defected panels over all = 4%

Now, 4% of (16,000 + m) = \frac{4}{100}  \times (16,000+m)  = (0.04)(16,000 + m)

Also, the total number of defective panels = Defective from A  + Defective from B

⇒(0.04)(16,000 + m)  =  800 +   0.02 m   from (1) and (2)

or, 640 + 0.04 m = 800 + 0.02

or, 0.02 m = 160

⇒ m = 160 /0.02 = 8,000

or, m = 8,000

Hence, Number of panels produced by Plant B is 8,000.

5 0
3 years ago
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