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2 years ago

9

(08.01)Consider the following system of equations:

1 answer:

Anika [276]2 years ago

5 0

Lines y = −2x + 3 and y = 3x – 5 intersect the x-axis.

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Find the value of the power. (2/3)3

Andreyy89

Answer:

The value is 27

Step-by-step explanation:

5 0

2 years ago

The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = y minus 4 equals StartFra

Stels [109]

Answer:

Third option: $y= \frac{1}{4}x+2$

Step-by-step explanation:

<h3><em> The correct form of the exercise is: "The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is $y -4 = \frac{1}{4}(x -8)$ . What is the slope-intercept form of the equation for this line?"</em></h3><h3><em /></h3>

<em> </em>The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

Given the equation of the line in Point-Slope form:

$y -4 = \frac{1}{4}(x -8)$

You need to solve for "y" in order to write the given equation of the line in Slope Intercept form.

Then, this is:

$y -4 = \frac{1}{4}(x -8)\\\\y-4= \frac{1}{4}x-\frac{8}{4}\\\\y-4= \frac{1}{4}x-2\\\\y= \frac{1}{4}x-2+4\\\\y= \frac{1}{4}x+2$

You can identify that the slope "m" is:

$m=\frac{1}{4}$

And the y-interecept "b" is:

$b=2$

7 0

3 years ago

Read 2 more answers

Differentiate y= ln l 1+t-t^3 l

lbvjy [14]

Y = ln |1 + t - t^3| = (1 - 3t^2)/(1 + t - t^3)

4 0

3 years ago

Help please! Step by steps

marin [14]

Area of the square bottom = L x W = 5 x 5 = 25 square cm

Area of triangle = 1/2 x base x height = 1/2 x 5 x 6 = 15 square cm

Total area = 25 + 15 = 40 square cm.

7 0

3 years ago

Find the area between the curve of y = x³ and the x-axis interval from x = 0 to x = 4.

dybincka [34]

If you are solving for y the anser is 64

3 0

2 years ago