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2 years ago

What’s the answer in this problem I’m stuck and can’t go forward

Mathematics

2 answers:

stiks02 [169]2 years ago

5 0

Subtract m<2 from KJL to find m<1
55-27=28 degrees

noname [10]2 years ago

4 0

M∠KJL-m∠2=m∠1
substitute,
55-27= 28
so m∠1 is 28°

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