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agasfer [191]
3 years ago
12

What’s the answer in this problem I’m stuck and can’t go forward

Mathematics
2 answers:
stiks02 [169]3 years ago
5 0
Subtract m<2 from KJL to find m<1
55-27=28 degrees 
noname [10]3 years ago
4 0
M∠KJL-m∠2=m∠1
substitute,
55-27= 28
so m∠1 is 28°
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