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kykrilka [37]
3 years ago
15

Whats the mean,median,mode,range for 86,90,93,85,79,and 92

Mathematics
1 answer:
Tasya [4]3 years ago
6 0
Mean 87.5
Median 88
Range 14
and Mode All values appeared just once
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Terry has a box of 144 colored pencils. If he and 4 of his friends share the pencils equally, how many pencils will be left over
monitta

Answer:

number of people=4+1

=5

144/5=28.5

28×5=140

Step-by-step explanation:

how many pencils will be left over?=144-140

=4

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2 years ago
The relative frequency of getting and even number is ___? What is it I got 28% and it says it's wrong.
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The frequency of getting an even number is 48%
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3 years ago
One number exceeds another by 26. the sum of the numbers is 58. what are the numbers
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First number = X

second number = x +26  ( exceeds means higher so add 26)

x + x+26 = 58

combine like terms:

2x + 26 = 58
 subtract 26 from each side:

2x = 58-26

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x = 32/2
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first number is 16
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5 0
3 years ago
2. The average human heart beats 60 beats per minute. How many times does a heart
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31536000

Step-by-step explanation:

if the average heart beats 60 beats per minute and there are 525600 minutes in a year multiply

4 0
2 years ago
Read 2 more answers
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
3 years ago
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