D it's undefined because it has no where else to go.
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Answer:
Question 1). Option C.
Question 2) Option C.
Question 3) Option D.
Step-by-step explanation:
Question 1), A. 7 - (9x + 3) = -9x -4
7 - 9x - 3 = -9x - 4
-9x + 4 = -9x - 4
Left hand side(L.H.S.)≠ Right hand side(R.H.S.)
Therefore, it's not an identity
B). 6m - 7 = 7m + 5 -m
6m -7 = 6m + 5
Again L.H.S.≠R.H.S.
So, it's not an identity.
C). 10p + 6 - p = 12p - 3(p - 2)
9p + 6 = 12p - 3p + 6
9p + 6 = 9p + 6
L.H.S.=R.H.S.
Therefore, it's an identity.
D). 3y + 2 = 3y - 2
L.H.S. ≠ R.H.S.
Therefore, it's not an identity.
Question 2. Part A. 7v + 2 = 8v - 3
7v - 8v = -2 - 3
- v = - 5
v = 5
Part B. 3x - 5 = 3x + 8 - x
3x - 5 = 2x + 8
3x - 2x = 8 + 5
x = 13
Part C. 4y + 5 = 4y - 6
This equation has no solution.
Part D. 7z + 6 = -7z - 5
7z + 7z = -6 - 5
14z = -11
z = ![-\frac{11}{14}](https://tex.z-dn.net/?f=-%5Cfrac%7B11%7D%7B14%7D)
Question 3). 5 + 7x = 11 + 7x
This equation has same coefficient of variable x on both the sides of the equation.
Therefore, equation has no solution.
Option D. no solution is the correct option.
Answer:
D
Step-by-step explanation:
Since each term has a negative, the expression has moved it to the front as multiplication of -1 to each term and grouped it with parenthesis.
Answer:
d=![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
Convert the fractions to have common denominators.
.
Now, isolate the "d" variable by doing the opposite operation and subtracting the 2/6 from both sides.
![\frac{5}{6} -\frac{2}{6} =\frac{3}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B6%7D%20-%5Cfrac%7B2%7D%7B6%7D%20%3D%5Cfrac%7B3%7D%7B6%7D)
Simply 3/6 and you should get 1/2.