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3 years ago

9

True or false an perpendicular cd < cad ~cbd

1 answer:

Ipatiy [6.2K]3 years ago

6 0

False is the correct answr

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Write 2⋅2⋅2⋅2⋅4⋅4⋅4 in exponential form

Lelechka [254]

Answer:

1024

Step-by-step explanation:

4 0

3 years ago

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Which table represents a linear function?<br>(i-ready diagnostic)

ycow [4]

Answer:

Step-by-step explanation:

If there are no exponents higher than 1, the function is linear.

8 0

3 years ago

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Please answer the 2 questions if you can? (This is my math from 8th grade)

LUCKY_DIMON [66]

Answer:

Hi myself Shrushtee.

Step-by-step explanation:

8) a) x = 8.

10) c) x = 3

please mark me as brainleist

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3 years ago

What are the roots of x in -10x2 + 12x − 9 = 0?

hoa [83]

Answer:

$x_1=\frac{3(2+i\sqrt{6})}{10}$

$x_2=\frac{3(2-i\sqrt{6})}{10}$

Step-by-step explanation:

Use the Quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

You can identify that, in this case:

$a=-10\\b=12\\c=-9$

Now you need to substitute these values into the formula:

$x=\frac{-12\±\sqrt{12^2-4(-10)(-9)}}{2(-10)}$

$x=\frac{-12\±\sqrt{-216}}{-20}$

Remember that:

$i=\sqrt{-1}$

Therefore,rewriting and simplifying, you get:

$x=\frac{-12\±6i\sqrt{6}}{-20}$

$x=\frac{-6(2\±i\sqrt{6})}{-2(10)}$

$x=\frac{3(2\±i\sqrt{6})}{10}$

Then, you get the following roots:

$x_1=\frac{3(2+i\sqrt{6})}{10}$

$x_2=\frac{3(2-i\sqrt{6})}{10}$

6 0

3 years ago

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Helppppppppppppp i need this homework done by today

lbvjy [14]

Answer: 13. -68

14. 36

15. -36

16. -3

17. 10

18. -4

19. 1310 ft

20. 330 ft

Step-by-step explanation:

13. 34*(-2)=-68

14. -9*(-4)=

-(9*(-4))=

-(-36)=36

15. 12*(-3)=-36

16. -12/4=-3

17. -20/(-2)=

20/2=10

18. 200/(-50)=-4

19. -1640*(-1)-(-330*(-1))=

1640-(-330*(-1))=

1640-330=1310 ft

20. -990*(-1)-(-660*(-1))=

990-(-660*(-1))=

990-660=330 ft

7 0

2 years ago