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3 years ago

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The Vertices of a parallelogram are A(-2, 6), B(3, 7), C(6, 2), and D(1, 1). The diagonals intersect at point P. what are the co

ordinates of point P?

1 answer:

kow [346]3 years ago

6 0

I do motetskw know

i have snowmen tho ☃︎

are the snow men cute i think they are ☃︎☃︎ so adorable i don t k ow what k am doing lol why are me u sks

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Find the missing side length

Mashcka [7]

It’s not 3 or 4 so I think 2

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3 years ago

Amir has RM565. He spent all his money buying b pieces of clothing which cost Rm70 per piece and k pairs of shoes which cost RM9

agasfer [191]

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70b+95k=565. I think it's like this

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2 years ago

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6th grade math ! help me please :)

malfutka [58]

1. N + 2; n = 6: the answer is 8 because n=6 so we sub n with that... and we get 6+2 and that’s 8.

2.5f; where f=4: the answer is 20 because when a variable is directly next to a number it is multiplied by that number so we will replace f with 4 and our equation is now 5(4) or 5•4 and both are equivalent to 20.

3. 7b-2; where b=5: the answer is 33 because 7 multiplied by 5(b) minus 2= 7(5)-2 or 7•5-2= 33 because you will multiply 7 by 5 and get 33 then you will subtract by 2 and get 33.

Hope this helps!!!

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3 years ago

Help me with this thing thanks anoarefi

ivann1987 [24]

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1. 8

2. 16

Step-by-step explanation:

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3 years ago

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Scores at a local high school on the American College Testing (ACT) college entrance exam follow the normal distribution with a

san4es73 [151]

Answer:

a) The mean is 18 and the standard deviation is 1.79.

b) The interpretation is that the standard deviation of the sample means of groups of 20 students will be of 1.79, which is the sample error, which is different from the population standard deviation.

c) 0.2005 = 20.05% probability that a sample of 20 students has a mean score of 19.5 or more.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 18 and a standard deviation of 8.

This means that $\mu = 18, \sigma = 8$

Sample of 20:

This means that $n = 20, s = \frac{8}{\sqrt{20}} = 1.79$

(a) Calculate the mean and standard deviation of the sampling distribution of x¯.

By the Central Limit Theorem, the mean is 18 and the standard deviation is 1.79.

(b) Interpret the standard deviation from part (a).

The interpretation is that the standard deviation of the sample means of groups of 20 students will be of 1.79, which is the sample error, which is different from the population standard deviation.

(c) Find the probability that a sample of 20 students has a mean score of 19.5 or more.

This is 1 subtracted by the pvalue of Z when X = 19.5. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{19.5 - 18}{1.79}$

$Z = 0.84$

$Z = 0.84$ has a pvalue of 0.7995

1 - 0.7995 = 0.2005

0.2005 = 20.05% probability that a sample of 20 students has a mean score of 19.5 or more.

7 0

3 years ago