(a) mtan refers to the slope of the tangent line. Given <em>f(x)</em> = 9 + 7<em>x</em> ², compute the difference quotient:
Then as <em>h</em> approaches 0 - bearing in mind that we're specifically considering <em>h</em> <em>near</em> 0, and not <em>h</em> = 0 - we can eliminate the factor of <em>h</em> in the numerator and denominator, so that
and so the slope of the line at <em>P</em> (0, 9), for which we take <em>x</em> = 0, is 0.
(b) The equation of the tangent line is then <em>y</em> = 9.
<span>For more difficult cases, it may be easier to draw the graph first using the domain if possible and then determine the range graphically.See if you can find the inverse function. The domain of a function's inverse function is equal to that function's range.<span>Check to see if the function repeats.</span></span>
Answer:
The length is 30 cubic yards.
Step-by-step explanation:
To find volume you use equation V=LxWxH
Since we already know the height, width, and volume we can input them into the equation.
18,720=L x 24 x 26
As you can see, the length is still unknown.
To figure it out though, you can multiply the height and width of the prism,
24 x 26 = 624
And then divide the volume, 18,720 by it.
18,720/624 = 30
Thus, your length is 30 cubic yards.
Answer:
C
Step-by-step explanation:
Area of rectangle A is 2 and area of B is 18. 18 divided by 2 is 9. Therefore rectangle B is 9 times the area of rectangle A
Answer:
The proportion of scores reported as 1600 is 0.0032
Step-by-step explanation:
Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).
In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)
The values of the cummulative distribution function of the standard Normal random variable, lets denote it are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600
Hence, the proportion of scores reported as 1600 is 0.0032.