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Nastasia [14]
3 years ago
8

Which description is true about ​pre-image ABC​ and ​image A′B′C′​ ?

Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

Option (C)

Step-by-step explanation:

From the graph attached,

In ΔABC and ΔA'B'C',

∠A ≅ ∠A'

∠B ≅ ∠B'

Therefore, ΔABC ~ ΔA'B'C'

Corresponding sides of these triangles will be proportional.

\frac{\text{AB}}{\text{A'B'}}=\frac{\text{BC}}{\text{B'C'}}=\frac{\text{AC}}{\text{A'C'}}=\frac{2}{6}

Therefore, ratio of the sides, AC : A'C' = 1 : 3 shows that image triangle A'B'C' is a dilated form of pre-image ABC with a scale factor of 3.

Option (C) will be the correct option.

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If x varies directly with y and x = 3.5 when y = 14, find x when y = 18.
maks197457 [2]

Answer:

x = 4.5

Step-by-step explanation:

there's definitely other ways to solve this, but I used a proportion.

\frac{3.5}{x} = \frac{14}{18}

Then you can make this equation:

14x = 3.5 * 18

I solved for it and got 4.5 .

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$1605

Step-by-step explanation:

since 100% = 1, just <em>multiply</em> 1 <em>(100% aka given price)</em> and 0.07 <em>(7%) </em>by 1500:

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4 years ago
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Answer:

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Step-by-step explanation:

K=5 /9(F−32)+273.15

Subtract 273.15 from each side

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K-273.15=5/9(F−32)

Multiply by 9/5 on each side

9/5 (K-273.15)= 9/5 *5/9(F−32)

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