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Nastasia [14]
3 years ago
8

Which description is true about ​pre-image ABC​ and ​image A′B′C′​ ?

Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

Option (C)

Step-by-step explanation:

From the graph attached,

In ΔABC and ΔA'B'C',

∠A ≅ ∠A'

∠B ≅ ∠B'

Therefore, ΔABC ~ ΔA'B'C'

Corresponding sides of these triangles will be proportional.

\frac{\text{AB}}{\text{A'B'}}=\frac{\text{BC}}{\text{B'C'}}=\frac{\text{AC}}{\text{A'C'}}=\frac{2}{6}

Therefore, ratio of the sides, AC : A'C' = 1 : 3 shows that image triangle A'B'C' is a dilated form of pre-image ABC with a scale factor of 3.

Option (C) will be the correct option.

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Answer:

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Step-by-step explanation:

From the given ∆TMZ, let the measure angle T be represented by T.

So that,

m<M = 2T + 6°

m<Z = 5T - 50°

Sum of angles in a triangle =

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Therefore,

i. m<T =

ii. m<M = 2T + 6°

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       =

m<M =

iii. m<Z = 5T - 50°

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Step-by-step explanation:

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2 years ago
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Answer:

<u>The system has two solutions:</u>

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Step-by-step explanation:

Let's solve the system of equations, this way:

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Replacing y in the 2nd equation:

y = x ² - 6x - 5

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x₂ = -2 ⇒ y₂ = 11

<u>As we can see the system has two different solutions</u>

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