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Nastasia [14]
3 years ago
8

Which description is true about ​pre-image ABC​ and ​image A′B′C′​ ?

Mathematics
1 answer:
scoray [572]3 years ago
7 0

Answer:

Option (C)

Step-by-step explanation:

From the graph attached,

In ΔABC and ΔA'B'C',

∠A ≅ ∠A'

∠B ≅ ∠B'

Therefore, ΔABC ~ ΔA'B'C'

Corresponding sides of these triangles will be proportional.

\frac{\text{AB}}{\text{A'B'}}=\frac{\text{BC}}{\text{B'C'}}=\frac{\text{AC}}{\text{A'C'}}=\frac{2}{6}

Therefore, ratio of the sides, AC : A'C' = 1 : 3 shows that image triangle A'B'C' is a dilated form of pre-image ABC with a scale factor of 3.

Option (C) will be the correct option.

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Harley wrote the expression shown to calculate the number of lawns he would mow in 3 months.
EastWind [94]

Answer:

Your answer is drum roll please...... D!

Step-by-step explanation:

3(4+9)

12+27

D. (3x4) + (3x9)

      12 +     27

Now hand me my money

7 0
3 years ago
I need help with this 2 please
xeze [42]

Answer:

D

Step-by-step explanation:

The formula for C is

C=2πr (using 3.14 as pi)

so C=2(3.14)(45)

so C=90(3.14)

so C≈282.6 or D

7 0
3 years ago
 Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find
Blababa [14]
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4 0
4 years ago
What is the surface area of the cylinder? Use 3.14 for pi and round your answer to the nearest hundredth.
kobusy [5.1K]

Answer:

Surface Area = 954.56

Step-by-step explanation:

The formula for Surface Area of a cylinder is 2πr² + 2πrh

Here the equation is (2 * 3.14 * 64) + (2 * 3.14 * 8 * 11) = 954.56

6 0
3 years ago
What is the denominator of the simplified expression? (StartFraction 2 n Over 6 n + 4 EndFraction) (StartFraction 3 n + 2 Over 3
Alexeev081 [22]

Answer:

<h3>The denominator of the given simplified expression is 3n-2</h3>

Step-by-step explanation:

Given expression is (\frac{2n}{6n+4})(\frac{3n+2}{3n-2})

<h3>To find the denominator of the simplified expression :</h3>

First simplify the given expression as below ;

(\frac{2n}{6n+4})(\frac{3n+2}{3n-2})

=(\frac{2n}{2(3n+2)})(\frac{3n+2}{3n-2}) ( here by taking the common term 2 outside the factor )

=(\frac{n}{1})(\frac{1}{3n-2}) ( here by simplifying the factors )

=\frac{n}{3n-2}

Therefore (\frac{2n}{6n+4})(\frac{3n+2}{3n-2})=\frac{n}{3n-2}

Therefore the result of the  given  simplified expression is \frac{n}{3n-2}

<h3>The denominator of the given simplified expression is 3n-2</h3>
8 0
4 years ago
Read 2 more answers
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