Answer:
Invasive species in time destory biodiversity of an ecosystems
Explanation:
So lets go over what each answer is:
Invasive species are species that invade a ecosystem, and can harm other species and take over resources.
Populatiuons are what make up an ecosystem. There are many populations in a single ecosystem.
Biotic factors are the living things found in the world.
Abiotic factors are the opposite, being the nonliving things found in the world.
Looking at these, which would eventually destroy the biodiversity(variation of species) of an ecosystem?
This would be invasive species, for it is the only answer that harms it's ecosystem.
And this is correct, for invasive species often times can cause extiction of species, or even whole ecosystems.
For example of an invasive species, if a tree-consuming and widly reporudcing insect that lives in plains, invades a pine forest, it will eventually kill off all the trees in the area.
This wont only kill off the pine trees, but harms and could potentiallu kill the species that depend on the pine trees for survival.
Answer: invasive speices.
Hope this helps!
Experiment 1 because it gave the same result every time
Answer:
a) 99.93%
b) 99.98%
Explanation:
Given that:
Total population size was only around 18 individuals ( for black-footed ferret)
If the annual survival rate in the wild was 0.4%.
a)
What is the probability that all 18 would have died in a single year?
To find that; we multiply the annual survival rate in the wild with the total population; which is:
(0.4%×18) = 0.072%
Then; we subtract it from a total of 100% in order to determine the probability that all 18 would have died in a single year.
= (100.00% - 0.072%)
= 99.93%
b)
What is the probability that all 18 would have died in a single year if canine distemper was present?
Given that;
Because of the presence of canine distemper disease, the annual mortality rate might have been as high as 0.89.
To determine the probability; we have:
1 - Annual mortality rate = annual survival rate
1 - 0.89 = 0.11 %
Therefore, 0.11% of 18 individuals = (0.0011 × 18)
= 0.0198%
Probability that all 18 would have died in a single year if canine distemper was present = 100 - probability of annual survival rate
= (100 - 0.0198)%
= 99.98%
Nitrogeneous bases
sugar
phosphate group
The answer is Closed. Hope it helps
