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joja [24]
3 years ago
8

Where dose 0.84 go on a number line

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
5 0

Answer: It depends on what kind, if the intervals are by 1, out it between 0 and 1, but closer to 1. If its by 1/2, put between .5 and 1. and so forth

Step-by-step explanation:

agasfer [191]3 years ago
3 0

It honestly depends on the kind of number line you have, it'd be between 0 and 1, very close to 1.  In the image below, you see a number line that includes tenths between 0 and 1, and they also include .84.

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In a raffle, one ticket is randomly chosen from 80 tickets to receive free haircuts for a year. If Jake entered 6 tickets, what
enyata [817]
Hi!

Jake has a 37/40 chance of losing the raffle or in fraction form, it would be a 92.5% chance of losing
3 0
3 years ago
Students are selling hand-made magnets at the school craft fair. One magnet costs $0.30, 2 magnets cost $0.43, 3 magnets cost $0
Sliva [168]
1 = 0.30 
2 = 0.43
3 = 0.56
4 = 0.69 
5 = 0.82
6=  0.95 

To find by how much you are adding every time , you have to subtract the 2 magnet cost (0.43) from the 1 magnet cost (0.30) and this equals 0.13
6 0
4 years ago
Which number is located between 15 and 20 on a number line?
jeyben [28]

Answer: 17.5  is located between them.

Step-by-step explanation:

To find out which number is located between the numbers, find their mean average which sum of the numbers divide by the number of values.

15 + 20 = 35

35 / 2 = 17.5

8 0
3 years ago
The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth
Bess [88]

Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE are equilateral \triangle s.

Area of an equilateral \triangle is defined as :

\dfrac{\sqrt{3}}{4} \times a^{2}

Where <em>a </em>is the side of \triangle.

Area of hexagon = 6 \times \dfrac{\sqrt{3}}{4}\times a^{2}

We are given that area of hexagon = 169.74 ft^{2}

Let <em>s </em>be the side of hexagon.

\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = 6 \times side

Perimeter = 6 \times 8.08

\Rightarrow 48.5 ft

So, perimeter of given regular hexagon is 48.5 ft.

6 0
3 years ago
Groks mother weighed
shusha [124]

Answer:

62 Kg

Step-by-step explanation:

Let g = weight of Grok last year in kg

m = weight of Grok's mother last year in kg

m = 3g

m-4 = 2(g+9)

since m = 3g

(3g)-4 = 2(g+9)

3g -4 = 2g + 18

3g-2g = 18+4

g = 22

m = 3*22

= 66

Note that:

g+9 = weight of Grok now

m-4 = weight of Grok's mother now

Grok weighs 31 Kg now

Grok's mother weighs 62 Kg now

4 0
3 years ago
Read 2 more answers
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