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2 years ago

I need help with my test

Mathematics

2 answers:

zavuch27 [327]2 years ago

7 0

Answer:

Step-by-step explanation:

Serga [27]2 years ago

6 0

Answer:

Nine is 76, no clue about eight

Step-by-step explanation:

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Jerome used 3 and 1/4 gallons of gasoline while driving from school to to his baseball game. If he originally had 7 gallons in h

kozerog [31]

7 - 3 1/4 = (turn mixed number to improper fraction
7 - 13/4 = (common denominator is 4)
28/4 - 13/4 =
15/4 or 3 3/4 gallons remain in the tank

6 0

3 years ago

Read 2 more answers

-2(b + 5) = 4 solve the equation for b

Vladimir79 [104]

Answer:

b = -7

Step-by-step explanation:

3 0

3 years ago

What is the nth term rule of the quadratic sequence below?

Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

Given sequence:

6, 20, 40, 66, 98, 136, ...

Calculate the first differences between the terms:

$6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136$

As the first differences are not the same, calculate the second differences:

$14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38$

As the second differences are the same, the sequence is quadratic and will contain an n² term.

The coefficient of the n² term is half of the second difference.

Therefore, the n² term is: 3n²

Compare 3n² with the given sequence:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

The second operations are different, therefore calculate the differences between the second operations:

$3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18$

As the differences are the same, we need to add 5n as the second operation:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2 &-2 & -2 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0

1 year ago

Need help ASAP pls. :)

Troyanec [42]

Answer:

Step-by-step explanation:

because we just multiply the bottom equation by - and we eliminate 7y. now we have -2x=-10 to get x we divide -10 by -2 and get the answer

7 0

3 years ago

Please need help thank you

jenyasd209 [6]

Answer:

q.4 is 24 pages

q.5 is 27 yrs. old

7 0

3 years ago