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goldenfox [79]
3 years ago
11

Is it possible to study just one atom? ?

Physics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:It is not possibly

Explanation:

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An elephant's legs have a reasonably uniform cross section from top to bottom, and they are quite long, pivoting high on the ani
PilotLPTM [1.2K]

Answer:

 t = 6,485 s ,  t_step = 25.94 s

the elephant gives 2.3 step very minute

Explanation:

Let's approximate this system to a simple pendulum that has angular velocity

            w = √L / g

Angular velocity and period are related

           w = 2π / T

           T = 2π √g / L

Let's find the period

           T = 2π √9.8 / 2.3

           T = 12.97 s

Stride time is

           t = T / 2

           t = 12.97 / 2

           t = 6,485 s

Frequency is inversely proportional to period

            f = 1 / t

            f = 1 / 6,485

            f = 0.15 Hz

Since the elephant has 4 legs and each uses a time t, the total time for one step is

            t_step = 4 t

            t_step = 4 6.485

            t_step = 25.94 s

             f_step = 1/t_step =0.0385 s-1

Now let's use a proportion rule to find the number of steps in 60 s

           #_step = 60 / t_step

           #__step = 60 / 25.94

           #_step = 2.3 steps

So the elephant gives 2.3 step very minute

4 0
3 years ago
An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis.
bonufazy [111]
Vx=cos60(4)
x-component of velocity
<span>If you think about it, it makes a right triangle when you combine all the different types of forces together such as v, vx and vy. Then, you can use trigonometry and soh cah toa in order to figure out vx. </span>
6 0
3 years ago
An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remai
rjkz [21]

Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion:        Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

                       Vf = Vi + a×t

                       Vf = 0 + 2.4×3.6

                       Vf = 2.4×3.6

                       Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

5 0
3 years ago
Approximately how many kelvins are equal to 60°f? <br> a. 333 <br> b. 323 <br> c. 413 <br> d. 289
Afina-wow [57]
D. 289
Take the formula:
K=5/9(Fahrenheit-32)+273
Plug in Fahrenheit
K=5/9 (60-32)+273
From here it is simple math and you can plug it into your calculator getting 288.5555556 and round to 289
3 0
3 years ago
Read 2 more answers
You have a lightweight spring whose unstretched length is 4.0 cm. First, you attach one end of the spring to the ceiling and han
sleet_krkn [62]

Answer:

2.2nC

Explanation:

Call the amount by which the spring’s unstretched length L,

the amount it stretches while hanging x1

and the amount it stretches while on the table x2.

Combining Hooke’s law with Newton’s second law, given that the stretched spring is not accelerating,

we have mg−kx1 =0, or k = mg /x1 , where k is the spring constant. On the other hand,

applying Coulomb’s law to the second part tells us ke q2/ (L+x2)2 − kx2 = 0 or q2 = kx2(L+x2)2/ke,

where ke is the Coulomb constant. Combining these,

we get q = √(mgx2(L+x2)²/x1ke =2.2nC

4 0
3 years ago
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