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2 years ago

You put a bottle of soft drink in a refrigerator and leave it until its temperature has dropped 12.0K .

Physics

1 answer:

Bingel [31]2 years ago

3 0

Answer: a) - 437.8° F, b) - 261°c.

Explanation: a) the kelvin and Fahrenheit temperature scale are related by the formulae below.

5 (°F - 32) = 9 (k - 273)

Where °F = temperature in Fahrenheit and k = temperature in kelvin.

For question A, k = 12.0, by substituting to have the value for °F, we have

5(°F - 32) = 9 ( 12 - 273)

5(°F - 32) = 9(-261)

5(°F - 32) = - 2349

°F - 32 = - 2349/5

°F - 32 = - 469.8

°F = - 469.8 + 32

°F = - 437.8

Question B

The centigrade and kelvin scale are related by the formulae below

°c = k - 273

Where °c = temperature in centigrade and k = temperature in kelvin =12

°c = 12 - 273

°c = - 261

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A 500 500500- kg kgstart text, k, g, end text object is accelerating to the right at 10 cm / s 2 10 cm/s 2 10, start text, space

enyata [817]

Given Information:

Mass = m = 500 kg

Acceleration = a = 10 cm/s²

Required Information:

Magnitude of rightward net force = F = ?

Answer:

Magnitude of rightward net force = 50 N

Explanation:

From the Newton's second law of motion

F = ma

Where m is the mass and a is the acceleration

To get force in Newtons first convert 10 cm/s² into m/s²

10/100 = 0.1 m/s²

F = 500*0.1

F = 50 N

Therefore, the magnitude of rightward net force acting on it is 50 Newtons.

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2 years ago

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Consider the vector field. f(x, y, z) = xy2z2i x2yz2j x2y2zk (a) find the curl of the vector field?

Marat540 [252]

Observe that the given vector field is a gradient field:

Let $f(x,y,z)=\nabla g(x,y,z)$ , so that

$\dfrac{\partial g}{\partial x} = x y^2 z^2$

$\dfrac{\partial g}{\partial y} = x^2 y z^2$

$\dfrac{\partial g}{\partial z} = x^2 y^2 z$

Integrating the first equation with respect to $x$ , we get

$g(x,y,z) = \dfrac12 x^2 y^2 z^2 + h(y,z)$

Differentiating this with respect to $y$ gives

$\dfrac{\partial g}{\partial y} = x^2 y z^2 + \dfrac{\partial h}{\partial y} = x^2 y z^2 \\\\ \implies \dfrac{\partial h}{\partial y} = 0 \implies h(y,z) = i(z)$

Now differentiating $g$ with respect to $z$ gives

$\dfrac{\partial g}{\partial z} = x^2 y^2 z + \dfrac{di}{dz} = x^2 y^2 z \\\\ \implies \dfrac{di}{dz} = 0 \implies i(z) = C$

Putting everything together, we find a scalar potential function whose gradient is $f$ ,

$f(x,y,z) = \nabla \left(\dfrac12 x^2 y^2 z^2 + C\right)$

It follows that the curl of $f$ is 0 (i.e. the zero vector).

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1 year ago

A rabbit trying to escape a fox runs north for 8.0 m, darts northwest for 1.0 m, then drops 1.0 m down a hole into its burrow. W

Andrews [41]

Answer: The net displacement is 6.40meters

Explanation:

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2 years ago

Time period of a simple pendulum is measured at Karachi. What change will occur in the time period, if it is measured on mount e

Reil [10]

The period of a pendulum is given by $T=2 \pi \sqrt{ \frac{l}{g} }$
since Karachi is near sea level, g is larger than it is on Mt. Everest. That means the pendulum will have a larger period on Mt. Everest than it would in Karachi.

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2 years ago

A donkey starts from rest and accelerates for 6.7 s at a rate of 1.6 m/s².

vitfil [10]

The maximum speed of the donkey is 10.72m/s

The question is based on the principle of motion in one dimension and hence formulas of motion in one dimension can be applied.

It is given that donkey attains an acceleration of 1.6 m/s^2

The time taken to accelerate to given speed is 6.7 seconds

We use the formula v=u + at to find the fastest speed

v is the final or maximum speed

u is the initial speed which in this case is 0 as the donkey is at rest

a is the acceleration of the donkey

t is the time taken in seconds

v = u + at

v= 0 + 1.6 x 6.7

= 10.72 m/s

Hence the donkey obtains the speed of 10.72 m/s

For further reference:

brainly.com/question/24478168?referrer=searchResults

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