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nevsk [136]
3 years ago
12

Suppose 500 joules of work is done to push an object in 15 seconds. Find the power for this situation

Physics
1 answer:
ohaa [14]3 years ago
5 0

Answer:

You have to calculate

Explanation:

Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F * d). A force of 10 newtons, that moves an object 3 meters, does 30 n-m of work.

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A force of 85 N is used to push a box along the floor a distance of 15 m. How much work was done?
denpristay [2]

Answer:

1275J

Explanation:

Given parameters:

Force on box  = 85N

Distance moved  = 15m

Unknown:

Work done  = ?

Solution:

Work done is the amount of force applied on a body to move it through a specific distance.

 Work done  = Force x distance

Now insert the parameters and solve;

 Work done = 85 x 15  = 1275J

4 0
3 years ago
Read 2 more answers
A wave created by shaking a rope up and down is called a.
Sidana [21]
A wave created by shaking a rope up and down is called a:
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5 0
2 years ago
The work done on a box is 532 joules. The force applied to the box was 48 N. What was the displacement of the box? *
Semenov [28]

Explanation:

Work = force × displacement

532 J = 48 N × d

d ≈ 11 m

8 0
3 years ago
What is the meaning of technology
slamgirl [31]
The exact definition of technology is: The application of scientific knowledge for practical purposes, especially in industry.

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5 0
3 years ago
Over a time interval of 1.99 years, the velocity of a planet orbiting a distant star reverses direction, changing from +20.7 km/
madam [21]

Answer:

(a) - 42700 m/s

(b) - 6.8 x 10^-4 m/s^2

Explanation:

initial velocity of star, u = 20.7 km/s

Final velocity of star, v = - 22 km/s

time, t = 1.99 years

Convert velocities into m/s and time into second

So, u = 20700 m / s

v = - 22000 m/s

t = 1.99 x 365.25 x 24 x 3600 = 62799624 second

(a) Change in planet's velocity = final velocity - initial velocity

  = - 22000 - 20700 = - 42700 m/s

(b) Accelerate is defined as the rate of change of velocity.

Acceleration = change in velocity / time

                     = ( - 42700 ) / (62799624) = - 6.8 x 10^-4 m/s^2

8 0
3 years ago
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