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Hoochie [10]
3 years ago
10

What causes a sonic boom?

Physics
2 answers:
aev [14]3 years ago
7 0
A sonic boom happens if you go faster than the speed of sound and that also makes the big loud sound you hear.
alekssr [168]3 years ago
7 0
It's caused by shock waves created by an object travelling faster than the speed of sound. The sound waves can't propegate ahead of the plane.
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A heater has a resistance of 10.0 Ω. It operates on a 12.0 V. What is the current through the resistor?
irakobra [83]

Answer:

1.2 amps :)

Explanation:

A heater has a resistance of 10.0 Ω. It operates on a 12.0 V. What is the current through the resistor?

         Known:

  • R = 10.0 Ω                            
  • V = 12.0 V

       Unknown:

  • I = ???

I = V/R

= 12.0 V / 10.0 Ω

= 1.2 amps

6 0
3 years ago
6- A metal block measures 10 cm x 2 cm x 2 cm. what is its volume? how many blocks each
zalisa [80]
You need 5 blocks of the smaller object to contain the same amount of volume of the bigger object

3 0
4 years ago
A car drives 215km east and then 45km north. What is the magnitude of the cars displacement? Round you answer to nearest whole n
kifflom [539]

Answer: 219.65\ \text{km}

Explanation:

Given

Car drives 215 km east and then 45 km North

Displacement is East direction is

\Rightarrow \vec{r_1}=215\hat{i}

Now, the displacement from that to 45 km North is given by

\Rightarrow \vec{r_{21}}=45\hat{j}

Net displacement is \vec{r_2}

\Rightarrow \vec{r_2}=\vec{r_1}+\vec{r_{21}}\\\Rightarrow \vec{r_2}=215\hat{i}+45\hat{j}

Magnitude of the displacement is

 \Rightarrow \left | r_{2} \right |=\sqrt{\left ( 215 \right )^2+\left ( 45 \right )^2}\\\Rightarrow  \left | r_{2} \right |=\sqrt{48250}\\\Rightarrow  \left | r_{2} \right |=219.65\ \text{km}

5 0
3 years ago
Ignoring air resistance, if you throw a baseball from first base upwards toward a friend in left field, and the baseball leaves
Mrac [35]
Slower then that because it can't stay 15 meters per second forever.
7 0
3 years ago
Read 2 more answers
Calculate the potential at the center of curvature of the arc if the potential is assumed to be zero at infinity.
yan [13]

the potential at the center of curvature of the arc = v = Q ∕ (4πε∘a) or \frac{kQ}{a}

ATQ,

We have density of charge,

λ = \frac{Q}{L}

Where L is the rod's length, in this case the semicircle's length L = πr

Q is the charge on the rod

The potential created at the center by an differential element of charge is:

k = \frac{dQ}{r}

where k is the coulomb's constant

r is the distance from dQ to center of the circle

v = ∫ \frac{K dQ}{a} , Where a = radius, k = 1 / 4πε∘

v =\frac{kQ}{a} or Q ∕ (4πε∘a)

To learn more about potential from the given link

brainly.com/question/25923373

#SPJ4

6 0
2 years ago
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