Answer:
s^ -1 ( or 1/sec)
Explanation:
Velocity is given in units of displacement / sec
like feet /sec or m/sec
so b would have units of s^-1
(or perhaps a more general term would be time^-1)
When t=2, the ball has fallen d(2) = 16 (2²) = 64 feet .
When t=5, the ball has fallen d(5) = 16 (5²) = 400 feet .
Distance fallen from t=2 until t=5 is (400 - 64) = 336 feet.
Time period between t=2 until t=5 is (5 - 2) = 3 seconds.
Average speed of the ball from t=2 until t=5 is
(distance covered) / (time to cover the distance)
= 336 feet / 3 seconds = 112 feet per second.
That's what choice-C says.
When a small cart collide with a large mass then during collision they must be in contact with each other for some interval of time
During this contact interval we can say they will exert normal force on each other
This normal force is always equal and opposite on two balls which means this force will follow Newton's III law
It will be same in magnitude but opposite in the direction
So here correct answer would be
<u><em>They both experience the same magnitude of the collision force.</em></u>
