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lidiya [134]
3 years ago
10

A certain compound is made up of one carbon (c) atom, two bromine (br) atoms, and one oxygen (o) atom. what is the chemical form

ula of this compound

Chemistry
2 answers:
padilas [110]3 years ago
7 0
Answer:
           Chemical Formula  =  COBr₂

           Structural Formula  =  Attached Below

           IUPAC Name  =  Carbonic Dibromide

           Common Name  =  Bromophosgene

As we know Carbon has the tendency to form four covalent bonds, Oxygen can form two covalent bonds and Bromine can form a single bond. Keeping this in mind we can say that in given compound carbon is forming two single bonds with two bromine atoms and a double bond with oxygen atom. Therefore, the valencies of all elements in the given compound are satisfied and completed.

Gennadij [26K]3 years ago
5 0

Answer:

The chemical formula of the compound will be COBr2.

Further details:

• The chemical formula of the compound is COBr2.

• The IUPAC name is Carbonic Dibromide

• The common name of the compound is Bromophosgene

As we know Carbon has the propensity to form four covalent bonds, Oxygen can form two covalent bonds and Bromine can form a single bond. Keeping this in mind we can say that in given compound carbon are making two single bonds with two bromine atoms and a double bond with oxygen atom. So, the valencies of all essentials in the given compound are fulfilled and accomplished.

Formation of Carbon dibromide:

Carbonyl bromide is made when carbon tetrabromide is melted and concentrated sulfuric acid is added.

In compare to phosgene, carbonyl bromide cannot be twisted efficiently from carbon monoxide and bromine. A complete alteration is not possible due to thermodynamic causes. Additionally, the reaction

                            CO + Br2 ⇌ COBr2

Answer details:

Subject: Chemistry

Level: College

Keywords:

  • Carbon dibromide
  • Formation of carbon dibromide
  • Carbon
  • Bromine
  • Oxygen

Learn more to evaluate:

brainly.com/question/4997492

brainly.com/question/4010464

brainly.com/question/1754173

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Answer:

Option B. 0.136 g

Explanation:

The balanced equation for the reaction is given below:

2AgNO3(aq) + 2NaOH(aq) —> Ag2O(s) + 2NaNO3(aq) + H2O(l)

Next, we shall determine the masses of AgNO3 and NaOH that reacted and the mass of Ag2O produced from the balanced equation. This is illustrated below:

Molar mass of AgNO3 = 108 + 14 + (16x3) = 170g/mol

Mass of AgNO3 from the balanced equation = 2 x 170 = 340g

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Molar mass of Ag2O = (108x2) + 16 = 232g/mol

Mass of Ag2O from the balanced equation = 1 x 232 = 232g

Summary:

From the balanced equation above,

340g of AgNO3 reacted with 80g of NaOH to produce 232g of Ag2O.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

340g of AgNO3 reacted with 80g of NaOH.

Therefore, 0.2g of AgNO3 will react with = (0.2 x 80)/340 = 0.047g of NaOH.

From the calculations made above, only 0.047g out of 0.2g of NaOH given, reacted completely with 0.2g of AgNO3. Therefore, AgNO3 is the limiting reactant and NaOH is the excess reactant.

Now, we can calculate the mass of Ag2O produced from the reaction of 0.2g of AgNO3 and 0.2g of NaOH.

In this case, we shall use the limiting reactant because it will produce the maximum yield of Ag2O as all of it is used up in the reaction.

The limi reactant is AgNO3 and the mass of Ag2O produced can be obtained as follow:

From the balanced equation above,

340g of AgNO3 reacted to produce 232g of Ag2O.

Therefore, 0.2g of AgNO3 will react to produce = (0.2 x 232)/340 = 0.136g of Ag2O.

Therefore, 0.136g of Ag2O was produced from the reaction.

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