<u>Answer:</u> The final temperature of the copper is 95°C.
<u>Explanation:</u>
To calculate the final temperature for the given amount of heat absorbed, we use the equation:
![Q= m\times c\times \Delta T](https://tex.z-dn.net/?f=Q%3D%20m%5Ctimes%20c%5Ctimes%20%5CDelta%20T)
Q = heat absorbed = +133 J (heat is added to the system)
m = mass of copper = 5.00 g
c = specific heat capacity of copper = 0.38 J/g ° C
![\Delta T={\text{Change in temperature}}=T_2-T_1](https://tex.z-dn.net/?f=%5CDelta%20T%3D%7B%5Ctext%7BChange%20in%20temperature%7D%7D%3DT_2-T_1)
![T_1=25^oC](https://tex.z-dn.net/?f=T_1%3D25%5EoC)
Putting values in above equation, we get:
![+133J=5.00g\times 0.38J/g^oC\times (T_2-25)\\\\T_2=95^oC](https://tex.z-dn.net/?f=%2B133J%3D5.00g%5Ctimes%200.38J%2Fg%5EoC%5Ctimes%20%28T_2-25%29%5C%5C%5C%5CT_2%3D95%5EoC)
Hence, the final temperature of the copper is 95°C.
To get the theoretical yield of ammonia NH3:
first, we should have the balanced equation of the reaction:
3H2(g) + N2(g) → 2NH3(g)
Second, we start to convert mass to moles
moles of N2 = N2 mass / N2 molar mass
= 200 / 28 = 7.14 moles
third, we start to compare the molar ratio from the balanced equation between N2 & NH3 we will find that N2: NH3 = 1:2 so when we use every mole of N2 we will get 2 times of that mole of NH3 so,
moles of NH3 = 7.14 * 2 = 14.28 moles
finally, we convert the moles of NH3 to mass again to get the mass of ammonia:
mass of NH3 = no.moles * molar mass of ammonia
= 14.28 * 17 = 242.76 g
Possibly wet and unstable
Answer:
I'm sorry but I'm not doing the whole test
Explanation: