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vlada-n [284]
3 years ago
7

⚠️NO LINKS⚠️(it will get reported)

Chemistry
1 answer:
brilliants [131]3 years ago
6 0

Answer:

I'm thinking cooper but not sure

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If you add enzyme to a solution containing only the product(s) of a reaction, would you expect any substrate to form?
Masteriza [31]

Answer:

e

Explanation:

<em>Provided the reaction that leads to the formation of the products can proceed in both forward and backward directions, the correct answer would be yes because the reaction will proceed backward until equilibrium is reached.</em>

<u>For a reaction that can proceed both forward and backward, the addition of a catalyst increases the rate of reaction in both directions based on the fact that a catalyst cannot alter the equilibrium of a reaction. </u>

Hence, if an enzyme is added to the product of a reaction that has the potential to proceed in both forward and reverse reactions, a substrate would be expected to form because the reaction will proceed backward until an equilibrium is reached.

The correct option is e.

8 0
2 years ago
What volume of carbon dioxide gas can be collected from
alisha [4.7K]

Answer:

1.22 L of carbon dioxide gas

Explanation:

The reaction that takes place is:

  • CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

First we <u>determine which reactant is limiting</u>:

  • Calcium carbonate ⇒ 10.0 g CaCO₃ ÷ 100 g/mol = 0.10 mol CaCO₃
  • Hydrochloric acid ⇒ 0.100 L * 0.50 M = 0.05 mol HCl

So HCl is the limiting reactant.

Now we calculate the moles of CO₂ produced:

  • 0.05 mol HCl * \frac{1molCO_{2}}{1molHCl} = 0.05 mol CO₂

Finally we use PV=nRT to <u>calculate the volume</u>:

  • P = 1 atm
  • n = 0.05 mol
  • T = 25 °C ⇒ 25 + 273.16 = 298.16 K

1 atm * V = 0.05 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

  • V = 1.22 L
7 0
3 years ago
A certain radioactive nuclide has a half life of 1.00 hour(s). Calculate the rate constant for this nuclide. s-1 Calculate the d
Karo-lina-s [1.5K]

Answer:

k= 1.925×10^-4 s^-1

1.2 ×10^20 atoms/s

Explanation:

From the information provided;

t1/2=Half life= 1.00 hour or 3600 seconds

Then;

t1/2= 0.693/k

Where k= rate constant

k= 0.693/t1/2 = 0.693/3600

k= 1.925×10^-4 s^-1

Since 1 mole of the nuclide contains 6.02×10^23 atoms

Rate of decay= rate constant × number of atoms

Rate of decay = 1.925×10^-4 s^-1 ×6.02×10^23 atoms

Rate of decay= 1.2 ×10^20 atoms/s

8 0
2 years ago
Unless otherwise instructed, you may refer to the periodic table in the Chemistry: Problems and Solutions book for this question
Tom [10]
Answer: oxygen

There is the s,p,d and f blocks, from groups 1-2 that is the s block, 13-18 that’s the p block, 3-12 is the d block and the f would be lanthanide(#57-71) and actinide (#89-103).
8 0
2 years ago
Calculate the number of grams of Hydrogen required to produce 5.73 grams of water. 2H2+O2---&gt;2H2O 2 grams 0.636 grams 1.2 gra
rusak2 [61]

Explanation:

32

2H

2

+O

2

→2H

2

O

Molecular mass of H

2

=2 g/mol

Molecular mass of O

2

=32 g/mol

From the balanced chemical equation,

2×2=4 g of hydrogen requires 32 g of Oxygen to react completely

3 0
3 years ago
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