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ser-zykov [4K]
3 years ago
13

If you begin with 1250 grams of N2 and 225 grams of H2 in the reaction that forms ammonia gas (NH3), how much ammonia will be fo

rmed? What is the limiting reagent? How much of the reagent is left when the maximum amount of ammonia is formed?
(AP Chemistry summer homework packet)


Please help! Thanks. :)
Chemistry
1 answer:
barxatty [35]3 years ago
8 0
N₂+3H₂⇒ 2NH₃
m(NH₃)=1250+225*2=1700 grams
N₂ is the limiting <span>reagent.
1250 grams are</span><span> left when the maximum amount of ammonia is formed.</span>
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HOCl dissociative into which 2 ions
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Answer:

H+ and OCl-

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3 years ago
Calculate the mass of solute in 500cm³ of 1.5mol/dm³ sodium hydroxide solution​
sineoko [7]

Answer: The general formulae for moles is n=m/mr so now we have being given to find the mass so all we have to do is to change subject

Explanation:  so we have to change subject in this question to m= n× mr . so in the question below we have being given the mole as 1.5mol/dm³  so all we have to do is to find the molecular relative mass(mr) .

to find the molecular relative mass of sodium hydroxide (NAOH) we add all of the atomic masses of all the atoms present so here we have sodium oxygen and hydrogen atoms present.

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8 0
3 years ago
if a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, what is the final volume if the pressure of the g
NNADVOKAT [17]

If a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, then the final volume would be 11,943.8144 ml if the pressure of the gas is changed to 775 torr assuming that the amount and the temperature of the gas remain constant.

It is given that the initial pressure P₁ is 24,650Pa and initial volumeV₁ is 376ml and the final pressureP₂ is 775 torr. We need to find the final volume of the gas. The final volume could be found using the following formula:

P₁V₁ = P₂V₂

By substituting the values, we get

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9268400 = 776V₂

V₂ = 9268400/776

V₂ = 11,943.8144 ml

Therefore, the final volume of the gas would be 11,943.8144 ml

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