If you begin with 1250 grams of N2 and 225 grams of H2 in the reaction that forms ammonia gas (NH3), how much ammonia will be fo
1 answer:
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The formula for mole fraction is:
-(1)
The solubility of oxygen gas = 1.0 mmol/L (given)
1.0 mmol/L means 1.0 mmol are present in 1 L.
Converting mmol to mol:
So, moles of oxygen = 0.001 mol
For moles of water:
1 L of water = 1000 mL of water
Since, the density of water is 1.0 g/mL.
So, the mass of water is 1000 g.
Molar mass of water = 18 g/mol.
Number of moles of water =
Substituting the values in formula (1):
Hence, the mole fraction is .
Answer : The masses of calcium chloride and water used were, 352.6 g and 487.0 g.
Explanation :
As we are given that 42.0 % calcium chloride by mass that means 42.0 grams of calcium chloride present in 100 grams of solution.
In the solution or mixture, 42.0 % calcium chloride and 58.0 % (100-42.0=58.0) water.
Now we have to determine the mass of calcium chloride for 839.6 grams of solution.
As, 100 grams of solution contains 42.0 grams of calcium chloride
So, 839.6 grams of solution contains grams of calcium chloride
Thus, the mass of calcium chloride used is, 352.6 grams.
Now we have to determine the mass of water.
Mass of water = Mass of solution - Mass of calcium chloride
Mass of water = 839.6 g - 352.6 g
Mass of water = 487.0 g
Thus, the mass of water used is, 487.0 grams.