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GrogVix [38]
3 years ago
6

A student takes a part-time job to earn for summer travel. The number of hours, , the student has to work is inversely proportio

nal to the wage, , in dollars per hour. (a) Write an expression for the function . Note that "" is already provided. Do not include this in your submitted response to this question. MathPAD Response msnViewer_res_c07q_eoc_1_18_mathpad_57_svg ViewEdit (b) How many hours does the student have to work if the job pays an hour
Mathematics
1 answer:
Andrej [43]3 years ago
8 0

Answer:

(a) h = \frac{2400}{w}

(b)300 Hours

(c)150 Hours

(d)Reduced and halved.

(e) w = \frac{2400}{h}

Step-by-step explanation:

(a) The number of hours worked is inversely proportional to the wage.

This is written as:

h \propto \frac{1}{w} \\\text{Introducing variation constant k}\\h = \frac{k}{w}\\$Since the money to be raised is constant, k = $ \$2400\\Therefore, h = \frac{2400}{w}

(b)If the student earns $8 an hour

w=$8

\text{Number of Hours required, h} = \frac{2400}{8} =300 Hours

(c)When the wage per hour =$16

When w=$16

\text{Number of Hours required, h} = \frac{2400}{16} =150 Hours

The number of hours reduced and is in fact halved.

(d)

\text{When the wage per hour =w}, h = \frac{2400}{w}\\\text{When the wage per hour =2w}, h = \frac{2400}{2w}=\frac{1}{2}  X \frac{2400}{w} =\frac{h}{2}

The effect of raising the wage from $w to $2w per hour is that the number of hours required to work is reduced and exactly halved.

(e)The wage per hour is inversely proportional to the number of hours.

In fact,

\text{From h = }\frac{2400}{w}\\\text{Cross Multiplying}\\hw=2400\\\text{Dividing both sides by h}\\w = \frac{2400}{h}

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mariarad [96]
Answer : d

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3 years ago
I need this done plz
KIM [24]

Answer:

13. -28 = p

12. 5 = r

11. -12 = t

10. -8 = q

9. -77 = s

8. 9 = w

7. 12 = y

6. 3 = a

5. 9 = n

4. 3 = x

3. 12 = y

2. 5 = c

1. 5 = m

DON'T GET HOOKED

Step-by-step explanation:

13. 1 + p \div 7 = -3 \\ \\ p\div 7 = -4 \\ \\ -28 = p

12. 5[r + 4] = 45 \\ \\ r + 4 = 9 \\ \\ 5 = r

11. t \div 4 - 3 = -6 \\ \\ t \div 4 = -3 \\ \\ -12 = t

10. -4 + 11q = -92 \\ \\ 11q = -88 \\ \\ -8 = q

9. s \div 7 + 8 = -3 \\ \\ s \div 7 = -11 \\ \\ -77 = s

8. w \div 3 + 3 = 6 \\ \\ w \div 3 = 3 \\ \\ 9 = w

7. y \div 3 - 4 = 0 \\ \\ y \div 3 = 4 \\ \\ 12 = y

6. 3[a + 5] = 24 \\ \\ a + 5 = 8 \\ \\ 3 = a

5. 14 = 2n - 4 \\ \\ 18 = 2n \\ \\ 9 = n

4. 3x + 6 = 15 \\ \\ 3x = 9 \\ \\ 3 = x

3. 6y - 11 = 61 \\ \\ 6y = 72 \\ \\ 12 = y

2. 9c - 4 = 41 \\ \\ 9c = 45 \\ \\ 5 = c

1. 2m + 2 = 12 \\ \\ 2m = 10 \\ \\ 5 = m

D O N ' T G E T H O O K E D

___ ___ ___ ___ ___ ___ ___ ___ ___ ___ ___ ___ ___

6 1 10 3 9 8 7 13 2 12 11 5 4

I am delighted to assist you anytime!

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Answer:

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And the confidence interval is given by:

(0.123, 0.177)

And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And the confidence interval is given by:

(0.123, 0.177)

And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

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Answer:

-12.90, -12.55, 10.25, 10.75, 12.50

Step-by-step explanation:

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