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3 years ago

Why do objects in orbit appear to be weightless?

Physics

1 answer:

ahrayia [7]3 years ago

4 0

Their velocity allows them to remain in orbital motion while the force of gravity pulls them inward.

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Why does a stationary electromagnet attached to an AC source induce current in a wire coil?

lora16 [44]

This is basically Michael Faraday's law and this is known as electromagnetic induction

That's all I know

4 0

3 years ago

Which image illustrates why dark clothing helps to keep you warm on a cool, sunny day?

xeze [42]

Answer:

Explanation:

I suppose it has to do with the way the diagram is drawn. The heat does not reflect which makes both A and B incorrect.

C would have nothing to do with either reflection or refraction.

That only leaves D which is the answer.

7 0

3 years ago

Read 2 more answers

A 0.8 kg bead slides on a curved wire, starting

TEA [102]

Answer:

vB = 12 m/s

W = 36 J

Explanation:

Potential energy converts to kinetic energy

½mv² = mgh

v = √(2gh)

vB = √(2(9.8)(7.1 - 0) = 11.796609... m/s

W = mg(hA) - mg(hB) = 0.8(9.8)(7.1 - 2.5) = 36.064 J

3 0

3 years ago

A uniform rod of mass M and length L is free to swing back and forth by pivoting a distance x from its center. It undergoes harm

Alisiya [41]

Answer:

The moment of inertia is 0.7500 kg-m².

Explanation:

Given that,

Mass = 2.2 kg

Distance = 0.49 m

If the length is 1.1 m

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=\dfrac{1}{12}ml^2+mx^2$

Where, m = mass of rod

l = length of rod

x = distance from its center

Put the value into the formula

$I=\dfrac{1}{12}\times2.2\times(1.1)^2+2.2\times(0.49)^2$

$I=0.7500\ kg-m^2$

Hence, The moment of inertia is 0.7500 kg-m².

5 0

3 years ago

A three-wheeled car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed

DiKsa [7]

Answer:

(a) Total time = 105.5 sec

(b)average speed = 31.26 m/sec

Explanation:

We have given that three-wheeled car starts from rest that initial velocity u = 0 m/sec

Final velocity = 35 m/sec

Acceleration $a=2m/sec^2$

According to first law of motion we know that v = u+at

So $35=0+2\times t$

t = 17.5 sec

After this car travels 83 sec at a constant speed and after that it takes 5 sec additional time to stop

(a) So total time in which car is in motion = 17.5+83+5 = 105.5 sec

(b) Total distance traveled during first 17.5 sec

$s=ut+\frac{1}{2}at^2=0\times 17.5+\frac{1}{2}\times 2\times 17.5^2=306.25m$

Distance traveled in 83 sec with with velocity of 35 m/sec = $35\times 83=2905m$

For next 5 second

Initial velocity u = 35 m/sec

Final velocity = 0 as finally car stops

So $a=\frac{v-u}{t}=\frac{0-35}{5}=-7m/sec^2$

Distance traveled $s=ut+\frac{1}{2}at^2=35\times 5+\frac{1}{2}\times -7\times 5^2=87.5m$

So total distance traveled = 306.25+2905+87.5 = 3298.75 m

Total time = 105.5 sec

So average speed $=\frac{total\ distance}{total\ time }=\frac{3298.75}{105.5}=31.26m/sec$

5 0

3 years ago