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Marina CMI [18]
3 years ago
14

A stick of mass m and length / is pivoted at one

Physics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

  • Potential Energy = mgl (1 - cosθ)

Explanation:

<h3>Given :-</h3>
  • Mass of stick = m
  • Length of stick = l
  • Angle = θ

<h3>To Find :-</h3>
  • Increase potential energy

<h3>Solution :-</h3>

✪ <u>According to the given </u><u>data</u> :-

 ⠀⠀⠀→ cosθ = ᵇ/ₕ

 ⠀⠀⠀→ cosθ = ᴬᴮ/l

 ⠀⠀⠀→ AB = l cosθ

❂ <u>For </u><u>Height</u> :-

 ⠀⠀⠀→ h = l - l cosθ

 ⠀⠀⠀→ h = l (1-cosθ)

☯ <u>As we know that</u>

 ⠀⠀⠀→ Potential Energy = mgh

 ⠀⠀⠀→ Potential Energy = mg × l (1-cosθ)

 ⠀⠀⠀→ Potential Energy = mgl (1-cosθ)

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Lemur [1.5K]

Answer: seven f orbitals

Explanation:

7 0
3 years ago
A 9Ω resistance is cut into three equal parts and connected in parallel. Find the equivalent resistance of the combination.​
sammy [17]

Answer:

the ans i 1 ohm

Explanation:

if i cut a resistor of 9 ohm into 3 equal parts then each resistor will have a resistance of 3 ohm and if they are in parallel combination the net resistance will be R

so 1/R=1/R1+1/R2+1/R3

     1/R=1/3+1/3+1/3

      R=1

7 0
3 years ago
Tabitha hit a 0.25 kg volleyball straight up into the air with 45 Joules of energy. How high did volleyball soar up? Round to th
zavuch27 [327]

Answer:

18 m

Explanation:

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7 0
4 years ago
Bone has a Young's modulus of about
saveliy_v [14]

Answer: 4.74 mm

Explanation:

We can solve this problem with the following equation:

Y=\frac{stress}{strain} (1)

Where:

Y=1.8(10)^{10} Pa is the Young modulus for femur

stress=\frac{F}{A}=1.58(10)^{8} Pa is the stress (force F applied per unit of transversal area A) on the femur

strain=\frac{\Delta l}{l_{o}}

Being:

\Delta l the compression the femur can withstand before breaking

l_{o}=0.54 m is the length of the femur without compression

Writing the data in equation (1):

Y=\frac{\frac{F}{A}}{\frac{\Delta l}{l_{o}}} (2)

1.8(10)^{10} Pa=\frac{1.58(10)^{8} Pa}{\frac{\Delta l}{0.54 m}} (3)

Isolating \Delta l:

\Delta l=\frac{(1.58(10)^{8} Pa)(0.54 m)}{1.8(10)^{10} Pa} (4)

\Delta l=0.00474 m (5) This is the compression in meters

Converting this result to millimeters:

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4 0
4 years ago
a teacher drives from school to the mall. then she goes to the doctors office for a physical examination. what is the magnitude
Amanda [17]

The magnitude of the teachers displacement is the difference between

the location of the school and the location of the doctors office

The reason behind the above expression are explained as follows

The known locations of the teacher;

Initial location; The school

Second location; The mall

The eventual location; The doctors office

The required information;

The magnitude of the teachers displacement

The method of obtaining the displacement of the teacher;

Qualitatively, the displacement of the teacher can be obtained by applying the definition of displacement as follows;

The definition of displacement is an object's change in position, given by the difference between its start and finish locations

According to the definition of displacement, therefore, the magnitude of

the teachers displacement is the distance between the school and the

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The magnitude of the displacement of the teacher = The coordinate of the location of the doctors office - The coordinate of the location of the school

Learn more about displacement here;

brainly.com/question/17587058

5 0
3 years ago
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