Question

A positive charge of 94. 0 nc is 22. 0 cm from a negative charge of 53. 0 nc. the force on one of the charges due to the other is approximately________.

Answer 1

A positive charge of 94. 0 NC is 22. 0 cm from a negative charge of 53. 0 NC. The force on one of the charges due to the other is approximately 92.6× 10⁹ N

Force between the two charges depends upon the charges, distance between the charges and the medium between the two charges. It is given by:

F = kq₁q₂ / r²

where q₁ is the charge of the first charge

q₂ is the charge of the second charge

r is the distance between the charges

k is the permitivitty of medium

F is the force between the two charges

Given ,  q₁ = 94NC

q₂  = 53NC

r = 22cm = 0.22m

On subsituting,

F = 9 × 10⁹ × 94 × 53 / (0.22)²

⇒ F = 92.6 × 10⁹ N

Since, the force between the two charges is equal on both the charges hence, force on one of the charges due to the other is approximately 92.6× 10⁹ N.

Learn more about Force here, brainly.com/question/11516376

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