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Mumz [18]
2 years ago
7

A positive charge of 94. 0 nc is 22. 0 cm from a negative charge of 53. 0 nc. the force on one of the charges due to the other i

s approximately________.
Physics
1 answer:
Lady_Fox [76]2 years ago
3 0

A positive charge of 94. 0 NC is 22. 0 cm from a negative charge of 53. 0 NC. The force on one of the charges due to the other is approximately 92.6× 10⁹ N

Force between the two charges depends upon the charges, distance between the charges and the medium between the two charges. It is given by:

F = kq₁q₂ / r²

where q₁ is the charge of the first charge

q₂ is the charge of the second charge

r is the distance between the charges

k is the permitivitty of medium

F is the force between the two charges

Given ,  q₁ = 94NC

q₂  = 53NC

r = 22cm = 0.22m

On subsituting,

F = 9 × 10⁹ × 94 × 53 / (0.22)²

⇒ F = 92.6 × 10⁹ N

Since, the force between the two charges is equal on both the charges hence, force on one of the charges due to the other is approximately 92.6× 10⁹ N.

Learn more about Force here, brainly.com/question/11516376

#SPJ4

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If a star is hotter is the wavelength shorter and higher energy?
insens350 [35]

Answer:

That is true, the hotter a star is the shorter of wavelength it emits and the higher. It also depends on the mass of the star because the bigger it is, the faster it fuses its hydrogen fuel. Faster burning of fuel means more energy is released and so results in higher temperatures.

Hope this helps! Good luck :)

Explanation:

3 0
3 years ago
Read 2 more answers
A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east​
elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: 56.31^o

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\

Now we can find the value of the angle by using the arctan function:

tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o

6 0
3 years ago
During a lie detector test, a voltage of 6V is impressed across two fingers. When a certain question is asked, the resistance be
sdas [7]

The current initially through the fingers is : 1.5 * 10⁻⁵ amp

The current when the resistance between them drops is : 3 * 10⁻⁵ amp

<u>Given data : </u>

Voltage ( V ) = 6 V

Initial resistance ( r ) = 400,000 ohms

Final resistance ( R ) = 200,000 ohms

<h3>Determine The Current </h3>

A) initially through fingers

I = V / r

 = 6 V / 400,000

 = 1.5 * 10⁻⁵ amp

B) when the resistance between them drops

I = V / R

 = 6 V / 200000

 = 3 * 10⁻⁵ amp

Hence we can conclude that The current initially through the fingers is : 1.5 * 10⁻⁵ amp and The current when the resistance between them drops is : 3 * 10⁻⁵ amp

Learn more about current calculation : brainly.com/question/25922783

6 0
2 years ago
Consider a river flowing toward a lake at an average velocity of 3 m/s at a rate of 500 m3/s at a location 90 m above the lake s
WINSTONCH [101]

Answer: a) 5 x 10^5 kg/s b) 444 MW

Explanation:

Kinetic energy per unit mass Ke is

Ke = V^2 / 2

Ke = 3^2 / 2 = 4.5 J/kg = 0.0045 kJ/kg

Now potential energy per unit mass Pe is

Pe = g x z = 9.8 x 90 = 882.9 J/kg = 0.8829 kJ/kg

The total mechanical energy of the River per unit mass e = Ke + Pe = 0.0045 + 0.8829 = 0.88744 J/kg

M = P x V = 1000 x 500 = 5 x 10^5 kg/s

b) power generation potential of the entire river at the location Wmax = Emech = M x Emech = 500,000 x 0.88744 = 444,000kW = 444MW

7 0
4 years ago
A particular motor can provide a maximum torque of 110 n • m. assuming that all of this torque is used to accelerate a solid, un
hjlf

Using the rotational equivalent of force:

Which is T = I*Alpha

Where: T is torque, I is the moment of inertia and Alpha is the angular acceleration. 

This is for the flywheel: J = 1/2mr^2 = 5*3^2 = 45 kgm^2 


From the equation: 


T = J*dω/dt 


we get: 


Δt = J*Δω/T = 45*8.13/110.0 = 3.326 sec

5 0
4 years ago
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