Answer:1.47
Explanation:
I got it correct on accelus
The speed he was moving at when he finished falling is 30 m/s.
The given parameters;
mass of the bungee, m = 80 kg
impulse provided by the rope, J = 3200 Ns
initial upward velocity of the jumper, u = 10 m/s
- Let the final velocity after falling = v
- Let the upwards motion = negative
- Let the downwards motion when falling = positive
Apply the principle of conservation of linear momentum;
J = ΔP = Δmv = m(v - u)
3200 = 80(v - (-10))
3200 = 80(v + 10)

Thus, the speed he was moving at when he finished falling is 30 m/s.
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