Answer:
Magnitude of the force is 2601.9 N
Explanation:
m = 450 kg
coefficient of static friction μs = 0.73
coefficient of kinetic friction is μk = 0.59
The force required to start crate moving is 
.
but once crate starts moving the force of friction is reduced .
Hence to keep crate moving at constant velocity we have to reduce the force pushing crate ie .
Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as forces are balanced.
Magnitude of the force
Answer:
50 W
Explanation:
<h3>
<u>Given :</u></h3>
- Force applied = 100 N
- Distance covered = 5 metres
- Time = 10 seconds
<h3>
<u>To find :</u></h3>
Power
<h3>
<u>Solution :</u></h3>
For calculating power, we first need to know about the work done.
Now, substituting values in the above formula;
Work = 100 × 5
= 500 Nm or 500 J
We know that,
Substituting values in above formula;
Power = 500/ 10
= 50 Nm/s or 50 W
Hence, power = 50 W .
The best option is C. This is due to friction.
Answer:
Explanation:
Given
See attachment
Required
Determine PCD and CPD
First, we need to calculate CPD
Since DPA is a straight line and CPA = 100;
We have that:
--- angle on a straight theorem
Substitute 100 for CPA
Subtract 100 from both sides
Next, we calculate PCD
We have that:
--alternate angle
In triangle PCD
--- angles in a triangle
Where
So, we have:
Subtract 136 from both sides
The answer to this question is false
