What level of intensity is bicycling 5-9 mph on level terrain?

#1 a person weighs 540n on earth what is the persons mass.

bixtya [17]

Answer:

G on earth =10N/Kg

W= mg

540= m x 10

m = 540/10

m= 54 Kg

W= mg

W= 66 x 10

W= 660 N

G on moon =1.6 N/Kg

#1

W= mg

W= 54 x 1.6

W=86.4 N

#2

W=mg

W= 66 x 1.6

W= 105.6 N

8 0

2 years ago

1000 kg of water initially at 6 m/s runs through a hydro-generator. If the water leaves the generator at velocity of 4 m/s, and

r-ruslan [8.4K]

Answer:

8.00 kJ

Explanation:

The first thing is to determine what quantities are there.

the mass of water = 1 000 kg

initial velocity, u = 6 m/s

final velocity, v = 4 m/s

the generator is operating at 100 % efficiency, so there is no energy loss.

The kinetic energy, Ek is converted to electrical energy, therefore Ek = electrical energy.

The kinetic energy is calculated as follows:

Ek = 1/2 mv²

= 1/2×(1 000)× (4)²

= 8 000 J/s

= 8.00 kJ Ans

4 0

3 years ago

A sled of mass 15 kg slides across the ground with a friction force of 80.85 N. What is k between the sled and the ground?

Dvinal [7]

The expression for the frictional force between the sled and the ground is:
$F=k m g$
where $k$ is the coefficient of friction, m is the mass of the object and $g=9.81 m/s^2$ is the gravitational acceleration.

The friction force in our problem is F=80.85 N. The mass of the object is m=15 kg. Re-arranging the formula, we can find the value of k:
$k= \frac{F}{mg}= \frac{80.85 N}{(15 kg)(9.81 m/s^2)}=0.55$

8 0

3 years ago

Read 2 more answers

How much work is required to accelerate a proton from rest up to a speed of 0.993 c? Express your answer with the appropriate un

Keith_Richards [23]

Answer:

(a). The work done is 7001 MeV.

(b). The momentum of this proton is $4.20\times10^{8}\ kg-m/s$ .