Answer:
Explanation:
Given:
Electric Flux = 
Side of sheet = 5cm
Area of the square sheet, A= 5×5 = 25cm²=25×10⁻⁴ m²
Now
the electric flux (Φ) is given as:
where, E = Electric field
or
substituting the values in the above equation, we get
Now the charge density (σ) on a sheet is given as:
where, 
= Permittivity of the free space = 8.85×10⁻¹²
substituting the values in the above equation, we get
Answer:
a.) The main scale reading is 10.2cm
b.) Division 7 = 0.07
c.) 10.27 cm
d.) 10.31 cm
e.) 10.24 cm
Explanation:
The figure depicts a vernier caliper readings
a.) The main scale reading is 10.2 cm
The reading before the vernier scale
b.) Division 7 = 0.07
the point where the main scale and vernier scale meet
c.) The observed readings is
10.2 + 0.07 = 10.27 cm
d.) If the instrument has a positive zero error of 4 division
correct reading = 10.27 + 0.04 = 10.31cm
e.) If the instrument has a negative zero error of 3 division
correct reading = 10.27 - 0.03 = 10.24cm
Answer:
%
%
Explanation:
From the exercise we know two information. The real speed and the experimental measured by the speedometer
Since the speedometer is only accurate to within 0.1km/h the experimental speed is
Knowing that we can calculate Kinetic energy for the real and experimental speed
Now, the potential error in her calculated kinetic energy is:
%
%
