During which type of change can an atom of carbon become an atom of nitrogen?

A horizontal 803-N merry-go-round is a solid disk of radius 1.41 m and is started from rest by a constant horizontal force of 49

Slav-nsk [51]

Answer:

The kinetic energy of the disk is 254.4 J.

Explanation:

The kinetic energy of the disk is given by:

$K = \frac{1}{2}I \omega^{2}$

The moment of inertia of the solid disk is:

$I = \frac{1}{2}mr^{2}$

The mass is:

$m = \frac{P}{g}$

$I = \frac{Pr^{2}}{2g} = \frac{803 N*(1.41 m)^{2}}{2*9.81 m/s^{2}} = 81.4 kgm^{2}$

Now, we need to find the angular acceleration as follows:

$\tau = I \alpha$

Also, the torque is related to the tangential force:

$\tau = F\times r$

$F\times r = I \alpha$

$\alpha = \frac{F \times r}{I} = \frac{49.7 N*1.41 m}{81.4 kg*m^{2}} = 0.86 rad/s^{2}$

Now, we can find the angular speed:

$\omega_{f} = \omega_{i} + \alpha t$

$\omega_{i} = 0$ since it is started from rest

$\omega_{f} = 0.86 rad\s^{2}*2.90 s = 2.50 rad/s$

Finally, the kinetic energy of the disk is:

$K = \frac{1}{2}I \omega^{2} = \frac{1}{2}81.4 kgm^{2}*(2.50 rad/s)^{2} = 254.4 J$

Therefore, the kinetic energy of the disk is 254.4 J.

I hope it helps you!

5 0

2 years ago

If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?

Bond [772]

Answer:

$g=25.92\ m/s^2$

Explanation:

Given that,

The mass of the Jupiter, $M=1.9\times 10^{27}\ kg$

The radius of Jupiter, $r=69,911\ km=69911\times 10^3 km$

We need to find the acceleration due to gravity on Jupiter. The formula is

$g=G\dfrac{M}{r^2}$

Put all the values,

$g=6.67\times 10^{-11}\times \dfrac{1.9\times 10^{27}}{(69911\times 10^3)^2}\\\\g=25.92\ m/s^2$

So, the value of acceleration due to gravity on the Jupiter is $25.92\ m/s^2$ .

6 0

2 years ago

PLEASE HELP THIS IS TIMED!

Monica [59]

3.5 because yea periodt

4 0

2 years ago

Suppose Tom Harmon17 is standing at the exact center of the Ohio State football field18 on the 50 yard line. The field is 300 fe

nignag [31]

Answer:

a) x = 40 t , y = 39 t , z = 6 + 32 t - 16 t ², b) x = 80 feet , y = 78 feet , the ball came into the field

Explanation:

a) This is a projectile launch exercise, where in the x and y axes there is no acceleration and in the z axis the acceleration of the acceleration of gravity, let's write the equations of motion in each axis

Since the cast is in the center of the field, let's place the coordinate system

x₀ = 0

y₀ = 0

z₀ = 6 feet

x-axis (towards end zone, GOAL zone)

x = xo + v₀ₓ t

x = 40 t

y-axis (field width)

y = y₀ + $v_{oy}$ t

y = 39 t

z axis (vertical)

z = z₀ + v_{oz} t - ½ g t²

z = 6 + 32 t - ½ 32 t²

z = 6 + 32 t - 16 t ²

b) The player catches the ball at the same height as it came out, so we can find the time it takes to arrive

z = 6

6 = 6 + 32 t - 16 t²

(t - 2)t = 0

t=0 s

t= 2 s

The ball position

x = 40 2

x = 80 feet

y = 39 2

y = 78 feet

the dimensions of the field from the coordinate system (center of the field) are

x_total = 150 feet

y _total = 80 feet

so we can see that the ball came into the field

6 0

2 years ago

How much energy is used when a 110kw appliance is used for 3 hours

Bogdan [553]

We could take the easy way out and just say

(110 kW) x (3 hours) = 330 kilowatt hours .

But that's cheap, and hardly worth even 5 points.
If we want to talk energy, let's use the actual scientific unit of energy.
________________________________________________

" 110 kw " means 110,000 watts = 110,000 joules/second .

(3 hours) x (3600 sec/hour) = 10,800 seconds.

(110,000 joules/second) x (10,800 seconds) = 1.188 x 10⁹ Joules

That's

==> 1,188,000,000 joules

==> 1,188,000 kilojoules

==> 1,188 megajoules

==> 1.188 gigajoules

Atsa nawfulotta energy !
It goes back to that "110 kw appliance" that we started with.
That's no common ordinary household appliance. 110 kw is something like
147 horsepower. In order to bring 110 kw into your house, you'd need to
take 458 Amperes through the 240-volt line from the pole. Most houses
are limited to 100 or 200 Amperes, tops. And the TRANSFORMER on
the pole, that supplies the whole neighborhood, is probably a 50 kw unit.

6 0

2 years ago