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dedylja [7]
3 years ago
13

A roller coaster track is 3000 meters long. It takes 100 seconds to travel once around the roller coaster. What is the average s

peed of the roller coast? Is the velocity constant throughout the trip? Explain
Physics
2 answers:
Svetllana [295]3 years ago
6 0
All you have to do is divide 3000 by 100, Its 30
mina [271]3 years ago
6 0

<u>Answer:</u> The average speed of the roller coast is 30 m/s

<u>Explanation:</u>

Average speed is defined as the ratio of total distance traveled to the total time taken.

To calculate the average speed of the runner, we use the equation:

\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}

We are given:

Total distance traveled by roller coast = 3000 m

Total time taken = 100 seconds

Putting values in above equation, we get:

\text{Average speed of roller coast}=\frac{3000m}{100s}=30m/s

Hence, the average speed of the roller coast is 30 m/s

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Eac of the two Straight Parallel Lines Each of two very long, straight, parallel lines carries a positive charge of 24.00 m C/m.
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Answer:

The magnitude of the electric field at a point equidistant from the lines is 4.08\times10^{5}\ N/C

Explanation:

Given that,

Positive charge = 24.00  μC/m

Distance = 4.10 m

We need to calculate the angle

Using formula of angle

\theta=\sin^{-1}(\dfrac{\dfrac{d}{2}}{2d})

\theta=\sin^{-1}(\dfrac{1}{4})

\theta=14.47^{\circ}

We need to calculate the magnitude of the electric field at a point equidistant from the lines

Using formula of electric field

E=\dfrac{2k\lambda}{r}\times2\cos\theat

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E=\dfrac{2\times9\times10^{9}\times24.00\times2\times10^{-6}\cos14.47}{2.05}

E=408094.00\ N/C

E=4.08\times10^{5}\ N/C

Hence, The magnitude of the electric field at a point equidistant from the lines is 4.08\times10^{5}\ N/C

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aalyn [17]
The answer would be etiquette!
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andreyandreev [35.5K]

Answer:

the answer choice is B

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