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dedylja [7]
3 years ago
13

A roller coaster track is 3000 meters long. It takes 100 seconds to travel once around the roller coaster. What is the average s

peed of the roller coast? Is the velocity constant throughout the trip? Explain
Physics
2 answers:
Svetllana [295]3 years ago
6 0
All you have to do is divide 3000 by 100, Its 30
mina [271]3 years ago
6 0

<u>Answer:</u> The average speed of the roller coast is 30 m/s

<u>Explanation:</u>

Average speed is defined as the ratio of total distance traveled to the total time taken.

To calculate the average speed of the runner, we use the equation:

\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}

We are given:

Total distance traveled by roller coast = 3000 m

Total time taken = 100 seconds

Putting values in above equation, we get:

\text{Average speed of roller coast}=\frac{3000m}{100s}=30m/s

Hence, the average speed of the roller coast is 30 m/s

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Answer:

1) 64.2 mi/h

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Explanation:

t = Time taken = 2.5 s

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1\ m=\frac{1}{1609.344}\ miles

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28.7\ m/s=\frac{\frac{28.7}{1609.344}}{\frac{1}{3600}}=64.2\ mi/h

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v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow t=\frac{21.7-0}{2.5}\\\Rightarrow a=8.68\ m/s^2

Acceleration of the cheetah is 8.68 m/s²

2)

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{28.7-0}{8.68}\\\Rightarrow t=3.31\ s

It takes a cheetah 3.31 seconds to reach its top speed.

3)

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{28.7^2-0^2}{2\times 8.68}\\\Rightarrow s=47.5\ m

It travels 47.5 m in that time

4) When s = 120 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 120=0\times t+\frac{1}{2}\times 8.68\times t^2\\\Rightarrow t=\sqrt{\frac{120\times 2}{8.68}}\\\Rightarrow t=5.26\ s

The time it takes the cheetah to reach a rabbit is 120 m is 5.26 seconds

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