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3 years ago

10 cm

Mathematics

1 answer:

kirza4 [7]3 years ago

7 0

Um can we see the cylinder

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Y=4mx-7b solve for x

muminat

Your answer is x = 7b/4m + y/4m

8 0

4 years ago

6y + 2 + 3 + 14y

hichkok12 [17]

Answer:

20y + 5

Step-by-step explanation:

6y + 2 + 3 + 14y

20y + 2 + 3

20y + 5

Have an amazing day!

PLEASE MARK BRAINLIEST!

3 0

3 years ago

Read 2 more answers

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

Which represents the value of What is the length of line segment DG?

Natalka [10]

<u>Answer</u>

12 units

<u>Explanation</u>

This can be solved using the properties of a circle.

DG and EG are secants f the circle.

DG×HG =EG×FG

(x+3+5)×5 = (x+6)×6

(x+8)5 = 6x + 36

5x +40 = 6x + 36

x = 4

DG = (x+3+5)

= 4 + 3 + 5

= 12 units

5 0

3 years ago

Read 2 more answers

What is the intersection (x, y) of the two lines generated by the 2 equations:

bearhunter [10]

Answer:

x=2

y=5

Step-by-step explanation:

y= x+3...(1)

y= -x+7...(2)

(1) + (2):

y+y= (x+3) + (-x+7)

2y= (x-x) + (3+7)

2y= 10

y= 5

By substituting y=5 into (1),

we have

5= x+3

x+3=5

x= 5-3

x= 2

3 0

3 years ago