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Vsevolod [243]
3 years ago
7

Factor the four-term polynomial.

Mathematics
2 answers:
Sliva [168]3 years ago
7 0
Q(p-3)p(q+r)
(p-3)(q-p)
Sveta_85 [38]3 years ago
7 0
Hello,

pq-3r+pr-3q=pq-3q+pr-3r=q(p-3)+r(p-3)=(p-3)(q+r)

Answer A

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Answer:

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RideAnS [48]

Step-by-step explanation:

Hey there!

Given;

f ( x ) = x² + 2x - 1

g ( x ) = 3x - 2

To verify:

( \frac{f}{g} )(2) =  \frac{f(2)}{g(2)}

LHS:

(\frac{f}{g} )(x) =  \frac{ {x}^{2}  + 2x - 1}{3x - 2}

~ Insert "2" instead of "x".

(\frac{f}{g} )(2) =  \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}

Simplify it;

\frac{f}{g} (2) =  \frac{4 + 4 - 1}{6 - 2}

Therefore; (f/g)(2) = 7/4.

RHS:

\frac{f(x)}{g(x)}  =  \frac{ {x}^{2}  + 2x - 1}{3x - 2}

~Insert "2" instead of"x".

\frac{f(2)}{g(2)}  =  \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}

Simplify it.

\frac{f(2)}{g(2)}  =  \frac{4 + 4 - 1}{6 - 2}

Therefore, f(2)/g(2) = 7/4.

Since (f/g)(2) = f(2)/g(2) = 7/4.

<em><u>Proved!</u></em>

<u>Hope </u><u>it </u><u>helps</u><u>!</u>

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40 - 2 to the second power•9+17 can you please show me how you got this answer and tell me what it is please I will mark brainie
ollegr [7]
Use orders of operations.
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